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IgorLugansk [536]
3 years ago
14

Draw the circuit symbol that would represent the 9V battery

Chemistry
1 answer:
lora16 [44]3 years ago
3 0
I hope this picture helps

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Prove that PV = nRT.​
qaws [65]

Find your answer in the explanation below.

Explanation:

PV = nRT is called the ideal gas equation and its a combination of 3 laws; Charles' law, Boyle's law and Avogadro's law.

According to Boyle's law, at constant temperature, the volume of a gas is inversely proportional to the pressure. i.e V = 1/P

From, Charles' law, we have that volume is directly proportional to the absolute temperature of the gas at constant pressure. i.e V = T

Avogadro's law finally states that equal volume of all gases at the same temperature and pressure contain the same number of molecules. i.e V = n

Combining the 3 Laws together i.e equating volume in all 3 laws, we have

V = nT/P,

V = constant nT/P

(constant = general gas constant = R)

V = RnT/P

by bringing P to the LHS, we have,

PV = nRT.

Q.E.D

6 0
3 years ago
Write balanced complete ionic equation for the reaction AgNO3(aq)+KCl(aq)→AgCl(s)+KNO3(aq).
Nikitich [7]
AgNO3(aq)  + KCl (aq)----->   AgCl(s) +  KNO3(aq)

Ag ^+(aq)   +  NO3^-(aq)  +  K^+ (aq)  +  cl^- (aq) ---->  AgCl(s)  +  K^+(aq)   +  NO3^-(aq)

net  ionic  equation
  Ag ^+(aq)   +  Cl^-(aq)   ---->  AgCl(s)
3 0
3 years ago
Read 2 more answers
Question 9 of 10
aksik [14]

Answer:

The answer is B an open system allows energy and mass to move in and out of it

Hope it helps

7 0
2 years ago
3-chloropropylamine what is?
marta [7]

Answer:

a chemical compound

6 0
2 years ago
Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighter would have to be burned to produce 17
Hitman42 [59]

<span>Answer is: mass of burned butane is 11.6 g.</span>

Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

m(butane) = 50,0 g.

<span> V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷ Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) : n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) = 0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) = 0,2 mol.<span>
m(C</span>₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) = 0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) = 11,6 g.

5 0
4 years ago
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