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arlik [135]
3 years ago
9

What is A mixture of very hot gas, falling ash and magma rock

Chemistry
1 answer:
Vsevolod [243]3 years ago
3 0

Volcanic sulfur    :) .    

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Fill the three 3d subshells with the specified number of electrons.
lana66690 [7]

1. 5 electrons.

3d^{5}

  • Therefore, the 3d subshells blanks will be like this:
  • ↑ ↑ ↑ ↑ ↑

2. 6 electrons.

3d^{6}

  • The 3d subshells blanks will be:
  • ↑↓ ↑ ↑ ↑ ↑

3. 7 electrons.

3d^{7}

  • The 3d subshells blanks will be:
  • ↑↓ ↑↓ ↑ ↑ ↑

Hope you could understand.

If you have any query, feel free to ask.

8 0
2 years ago
How many hydrogen atoms are represented by the formula below?
Sonbull [250]

Answer:

c 9

Explanation:

4 0
3 years ago
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Soils that allow water to pass through them faster are more
Kay [80]
The answer would be permeable because permeable means let's liquid through easily.
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3 years ago
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When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
2 years ago
How many atoms are in 0.0246 mol K?
Alexxx [7]

Answer:

There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K.

Explanation:

3 0
2 years ago
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