<u>Answer:</u> The law that related the ideal gas law is 
<u>Explanation:</u>
There are 4 laws of gases:
- <u>Boyle's Law:</u> This law states that pressure is inversely proportional to the volume of the gas at constant temperature.
Mathematically,

- <u>Charles' Law:</u> This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

- <u>Gay-Lussac Law:</u> This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

- <u>Avogadro's Law:</u> This law states that volume is directly proportional to number of moles at constant temperature and pressure.
Mathematically,

Hence, the law that related the ideal gas law is 
Answer:
heating the reactant mix
Explanation:
Heat can result in to speed the reaction process.
hope it helps!
Answer:
B-2
Explanation:
In the graph you can so that two of the shapes ae fully black, that means that they are color blind, the half colored ones means they are a carrier but they aren't color blind. So two males in the offspring are color blind.
Answer:

Explanation:
Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.
The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

The net equation is then:

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:
Actual anode half-equation:

Actual cathode half-equation:

Actual net reaction:
