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Virty [35]
3 years ago
6

Using this chemical might discolour equipment and surfaces​

Chemistry
2 answers:
Nataliya [291]3 years ago
5 0
Confused how to answer this
Rudiy273 years ago
3 0

Answer: do not know how to answer this

Explanation:

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3 years ago
If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
kodGreya [7K]

Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}

[Cu^{2+}]=0.041 M

Best regards!

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2 years ago
Balance this equation K+b2o3=k2o+b
AVprozaik [17]

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Explanation:

2K and 2b

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