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harina [27]
3 years ago
7

11.

Physics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

Explanation:

From the graph attached,

Values on y-axis represent the distance traveled by a particle at any moment of time 't' given at x-axis.

Velocity of the particle = \frac{\triangle y}{\triangle x}

a). At t = 1 s,

Position of the the point is at (1, 5).

Therefore, slope of the line = velocity of the particle

Velocity = \frac{\text{Distance traveled from x= 0 to x = 1}}{\text{Duration}}

             = \frac{5}{1} m per sec

             = 5 m per sec.

b). At t = 3 s,

Velocity of the particle = Slope of the segment on which the particle lies

Velocity = \frac{10-4}{4-2}

              = 3 m per sec.

c). At t = 4.5 s,

Velocity = 0 [Since distance traveled = 0]

d). At t = 7.5 s

Velocity = \frac{0+6}{8-7}

              = 6 m per sec.

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1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and
Arturiano [62]

The time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

<h3>What is center of gravity?</h3>

Any object of mass is attracted towards another by point where whole mass is supposed to be concentrated is called center of gravity.

A 1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and weighing 0.290 N.

The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached.

Taking moments about one end, to find the tension at other end.

Tb X L = WxL/3

here, W is the weight, L is the length of wire and Tb is the tension at point B.

So, Tb = W/3

and
Tb - Ta = W

here, Ta is the tension in end A.

Substitute the values, we get

Tb = 583.33N and Ta = 1166.66N

Velocity of end A, Va = (1166.66 x1.25 x 9.81/0.290 )^(1/2)

Va = 222 m/s

Velocity of end B, Vb = (583.33 x1.25 x 9.81/0.290 )^(1/2)

Va = 157 m/s

Time delay t is related with the velocities as

t = L/Vb - L/Va

Substitute the values, we get

t= 0.00233 s

t = 2.33 ms

Thus, time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

Learn more about center of gravity.

brainly.com/question/20662235

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8 0
2 years ago
What is surface tension and what phase of matter creates it?
hram777 [196]

Answer:

The property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.The cohesive forces between liquid molecules are responsible for the phenomenon known as surface tension.

If i'm wrong correct me.

4 0
3 years ago
Two oppositely charged parallel sheets of charge give rise to a field of 9.00×1011 N/C between them. The sheets are square and h
Maksim231197 [3]

Answer:

Q = 5.75 C

Explanation:

As we know that due to a thin sheet electric field at a point near its surface is given as

E = \frac{\sigma}{2\epsilon_0}

now we have two sheets of opposite charges so the net electric field is double that of field due to one sheet

so we have

E_{net} = 2E

E_{net} = \frac{\sigma}{\epsilon_0}

9.00 \times 10^{11} = \frac{Q}{A\epsilon_0}

now we have

Q = 9.00 \times 10^{11}(0.85 \times 0.85)(8.85 \times 10^{-12})

Q = 5.75 C

8 0
4 years ago
You are sitting 3 m away from you friend who is watching a cartoon on his phone. How will the sound itensity change if your frie
Zinaida [17]

Answer:

Decreases by $3.6 \times 10^{-3}$ times

Explanation:

The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.

The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance.  i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =  $\frac{1}{0.06^2}$

                       = $3.6 \times 10^{-3}$ times

3 0
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When an alarm clock rings, how will nearby air particles move in relation to the direction of the sound waves? A) Perpendicular
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Parallel to the direction of the waves
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