Question

11.

Answer 1

Answer:

Explanation:

From the graph attached,

Values on y-axis represent the distance traveled by a particle at any moment of time 't' given at x-axis.

Velocity of the particle = $\frac{\triangle y}{\triangle x}$

a). At t = 1 s,

Position of the the point is at (1, 5).

Therefore, slope of the line = velocity of the particle

Velocity = $\frac{\text{Distance traveled from x= 0 to x = 1}}{\text{Duration}}$

             = $\frac{5}{1}$ m per sec

             = 5 m per sec.

b). At t = 3 s,

Velocity of the particle = Slope of the segment on which the particle lies

Velocity = $\frac{10-4}{4-2}$

              = 3 m per sec.

c). At t = 4.5 s,

Velocity = 0 [Since distance traveled = 0]

d). At t = 7.5 s

Velocity = $\frac{0+6}{8-7}$

              = 6 m per sec.