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Paha777 [63]
3 years ago
14

Volume increases, pressure stays the same, temperature

Chemistry
1 answer:
Mila [183]3 years ago
4 0
Temperature decreases (?)
You might be interested in
Please help!!! DUE IN 10 minutes
NARA [144]

Answer:

90

   Th

    232.04

Explanation:

90 - atomic number

  Th - element symbol

    232.04 - atomic mass

4 0
3 years ago
The isomerization of methylisonitrile to acetonitrileCH3NC(g)→CH3CN(g)is first order in CH3NC . The rate constant for the reacti
lisabon 2012 [21]

Answer:

Option E, Half life = 2.96\times 10^3\ s

Explanation:

For a first order reaction, rate constant and half-life is related as:

            t_{1/2}=\frac{0.693}{k}

Where,

t_{1/2} = Half life

k = Rate constant

Rate constant given = 2.34\times 10^{-4}\ s^{-1}

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{2.34 \times 10^{-4}}=2.96\times 10^3\ s

So, the correct option is option E.

4 0
3 years ago
What is the ph of a solution of 0.700 m kh2po4, potassium dihydrogen phosphate?
GalinKa [24]
Molal or molar? There is a difference
4 0
3 years ago
Could the cuttlefish tell the difference between the blue and yellow in the lab?​
jeka94

Answer:

<em>yes</em>

Explanation:

the cuttle fish tell the difference between blue and yellow

5 0
1 year ago
What is the average atomic mass of chlorine if the mass of one isotope is 34.97 amu and has a p?er cent abundance of 75.77%. The
pishuonlain [190]

Answer : The average atomic mass of chlorine is, 32.37 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Mass of isotope 1 = 34.97 amu

Percentage abundance of isotope 1 = 75.77 %

Fractional abundance of isotope 1 = 0.7577

Mass of isotope 2 = 36.97 amu

Percentage abundance of isotope 2 = 24.23 %

Fractional abundance of isotope 2 = 0.2423

Now put all the given values in above formula, we get:

\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]

\text{Average atomic mass of element}=32.37amu

Therefore, the average atomic mass of chlorine is, 32.37 amu

8 0
3 years ago
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