Answer:
Total worth of gold in the ocean = $5,840,000,000,000,000
Explanation:
As stated in the question above, 4.0 x 10^-10 g of gold was present in 2.1mL of ocean water.
Therefore, In 1 L of ocean water there will be,
(4.0 x 10^-10)/0.0021
= 1.9045 x 10^-7 g of gold per Liter of ocean water.
So in 1.5 x 10^-21 L of ocean water, there will be
(1.9045 x 10^-7) * (1.5 x 10^-21)
= 2.857 x 10^14 g of gold in the ocean.
1 gram of gold costs $20.44, that is 20.44 dollars/gram. The total cost of the gold present in the ocean is
20.44 * (2.857 x 10^14)
= $5,840,000,000,000,000
<span>The pH of a vinegar solution is 4.15. To find the H+ concentration of the solution use the following equation -log(H+)=pH.
Insert the pH into the equation to get, -log(H+) = 4.15
Rearrange the equation to get, 10^(-4.15) = H+
Finally, you can solve for H+.
The hydrogen ion concentration of the vinegar solution is .0000708 M.</span>
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