To answer the question above, let x be the shorter one of the pieces. With the variable, we can express the longer piece as 2x + 3. Based on the given, the sum of the lengths of these pieces should sum up to 14 ft.
2x + 3 + x = 14 ft, x = 3 2/3 ft
Substituting this value for the longer piece, we get 10 1/3 ft. Thus, the lengths of the pieces are 3 2/3 ft and 10 1/3 ft.
6x³y + 6xy − 12x² − 12 = 6(xy-2) * (x²+1)
(x²+1) is a factor of 6x³y + 6xy − 12x² − 12
Answer: - 0.027
Step-by-step explanation:
Win = any even number between (0 - 36)
Therefore,
Lose = any odd number between 0 —36 including 0
Assume Bet amount = $1
Expected value is calculate by summing all possible outcomes by their respective probabilities.
Expected value = [(p(winning) × net win value) + (p(losing +net loss value]
P(winning) = p(even) = 18/37
P(losing) = p(odd) +p(0) = 19/37
Net win value = $2
Net loss value = $-1
Expected value = [(18/37) × ($1) + (19/37) × (-$1)]
Expected value = 0.48648648 - 0.51351351
Expected value = - 0.027
The inequality statement shows that both Jose and Sue landed on red or blue squares and hence both lost some points. The points they lost were more than the points they gained, which resulted in an overall score having a negative value for each player.
Jose had a final score of -2 and Sue had a final score of -5. This means, Sue scored less and probably lost more points as compared to Jose. There is a difference of 3 points between the scores of both players.
