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Helen [10]
3 years ago
11

What type of rock is oil formed in?

Chemistry
2 answers:
maria [59]3 years ago
6 0

Answer:

Sedimentary rock

Explanation:

Oil is made and trapped in sedimentary rocks

castortr0y [4]3 years ago
3 0

Answer:

Oil is formed and trapped in sedimentary rather than igneous rocks. Regions where the ancient precambrian igneous rocks are exposed at the surface of the Earth are called shields.

Explanation:

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!!!HELP ASAP!!! Which of the following is an example of a chemical change?
VikaD [51]
C. A solid dissolving
4 0
3 years ago
Jayden says that the dentist can shine a special light on his teeth that will make his teeth become whiter. Can light change Jay
arsen [322]

Answer:

No

Explanation:

This is because light cannot not whiten Jayden's teeth but light can change materials by hearing it up. There are some substances or tooth paste that can be use to whiten the teeth because of the content they are made off which whitens the teeth. Some of it include baking soda, hydrogen peroxide toothpaste, tumeric toothpaste, toothpaste that contain fluoride.

5 0
3 years ago
How many moles of pcl3 contain 3.68 × 1025 chlorine atoms?
disa [49]
To answer the question above, we take note first that every mole of PCl₃ contains 3 atoms of Cl. First, we divide the given number by 3.
                                   3.68 x 10²⁵ / 3 = 1.227 x 10²⁵ 
Then, we divide the answer by the Avogadro's number which is equal to 6.022 x 10²³. That is,
                                    1.227 x 10²⁵ / (6.022 x 10²³) = 20.37
Thus, there are 20.37 mol of PCl₃. 
4 0
3 years ago
Read 2 more answers
Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.4 ∘C. A 250 mL sealed flask contains
erastova [34]

Given that:

  • The heat of vaporization = 22.44 kJ/mol = 22440 J/mol
  • normal boiling point which is the initial temperature = 0.4° C = (273 + (-0.4))K  = 272.6 K
  • volume  = 250 mL = 0.250 L
  • Mass of butane = 0.8 g
  • the final temperature = -22° C = (273 + (-22)) K = 251 K

The first step is to determine the vapor pressure at the final temperature of 251K by using the Clausius-Clapeyron equation. This is following by using the ideal gas equation to determine the numbers of moles of butane gas. After that, the mass of butane present in the liquid is determined by using the relation for the number of moles.

Using Clausius-Clapeyron Equation:

\mathbf{In (\dfrac{P_2}{P_1} )= -\dfrac{\Delta H_{vap}}{R}(\dfrac{1}{T_2} - \dfrac{1}{T_1})}

where;

P1 and P2 correspond to the temperature at T1 and T2.

∴

replacing the values into the given equation, we have;

\mathbf{In \dfrac{P_2}{1\  atm} = -\dfrac{22440 \ J/mol}{8.314 \ J/mol.K}(\dfrac{1}{251 \ K} - \dfrac{1}{272.6 \ K})}

\mathbf{In \dfrac{P_2}{1\  atm} =-(0.852053785)}

\mathbf{P_2=0.427 \ atm}

As such, at -22° C; the vapor pressure = 0.427 atm

Now, using the ideal gas equation:

PV = nRT

where:

  • P = Pressure
  • V = volume
  • n = number of moles of butane
  • R = universal gas constant
  • T = temperature

∴

Making (n) the subject of the formula:

\mathbf{n = \dfrac{PV}{RT}}

\mathbf{n = \dfrac{0.427 atm \times 0.250 L}{(0.08206 \ L.atm/k.mol) \times 251}}

\mathbf{n =0.00518 mol}

We all know that the standard molecular weight of butane = 58.12 g/mol

∴

Using the relation for the number of moles which is:

\mathbf{number \  of \  moles = \dfrac{mass}{molar mass}}

mass = 0.00518 mole × 58.12 g/mol

mass = 0.301 g

∴

The mass of butane in the flask = 0.301 g

But the mass of the butane present as a liquid in the flask is

= 0.8 g - 0.301 g

= 0.499 g

In conclusion, the mass of the butane present as a liquid in the flask is 0.499 g

Learn more about vapourization here:

brainly.com/question/17039550?referrer=searchResults

7 0
3 years ago
HELP ASAP no links or I will report
Svetach [21]

Answer:

50 feet

Explanation:

I got it right

Brainliest plz

4 0
2 years ago
Read 2 more answers
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