The answer is 0.25 M
Use the equation C1V1=C2V2
(.5)(100)=x(200)
x=0.25
<h3>Answer:</h3>
The pressure will decrease by half.
<h3>Explanation:</h3>
Data Given:
P₁ = 101.3 kPa
V₁ = X
V₂ = 2X
P₂ = ??
Let us suppose the initial volume is 5 L and the final volume when doubled is 10 L. Then According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure". Mathematically the initial and final states of gas are given as,
P₁ V₁ = P₂ V₂ ----------- (1)
Solving equation 1 for P₂,
P₂ = P₁ V₁ ÷ V₂
Putting values,
P₂ = (101.3 kPa × 5 L) ÷ 10 L
P₂ = 50.65 kPa
<h3>Result:
</h3>
As the volume is doubled, the pressure is decreased from 101.3 kPa to 50.65 kPa or it has decreased by half.
Answer:
Light years are the only practical unit for measuring the distance of space
Explanation:
Practical... aka logical.
Answer:
Explanation:
This is an example of back titration.
You add a known excess of HCl to the CaCO₃. Some of it reacts with the CaCO₃.
You titrate the left-over HCl.
From the difference you can calculate the amount of CaCO₃.
100.09
CaCO₃ + 2HCl ⟶ CaCl₂ + H₂CO₃
m/g: 1.2450
V/mL: 65.00
c/mol·L⁻¹: 0.4984
NaOH + HCl ⟶ NaCl + H₂O
V/mL: 37.15
c/mol·L⁻¹: 0.2065
1. Total moles of HCl
2. Excess moles of HCl
3. Moles of HCl that reacted
n = (32.40 - 7.671) mmol HCl = 24.72 mmol HCl
4. Moles of CaCO₃
5. Mass of Ca