<em>number of waves that pass a given point in one second is called <u>frequency..</u></em>
Exercise is the activity and fitness is a lifestyle and done with time
Answer:
Initial velocity, U = 4.5m/s
Explanation:
Given the following data;
Final velocity, v = 12m/s
Time, t = 5 seconds
Acceleration, a = 1.5m/s²
To find the initial velocity, we would use the first equation of motion.
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
12 = U + 1.5*5
12 = U + 7.5
U = 12 - 7.5
Initial velocity, U = 4.5m/s
Answer:
H = 6.93 m
Explanation:
given data
velocity v = 35 m/s
horizontal component Vx = 33 m/s
solution
we get here maximum height so first we get vertical component here that is express as
Vy =
.........................1
put here value
Vy =
Vy = 11.66 m/s
and
now we get height
H =
.............................2
put here value
H = ![\frac{11.66^2}{2\times 9.8}](https://tex.z-dn.net/?f=%5Cfrac%7B11.66%5E2%7D%7B2%5Ctimes%209.8%7D)
H = 6.93 m
Answer:
Final velocity v=19.83 m/sec
Explanation:
We have given initial velocity u =5.13 m/sexc
Acceleration of automobile ![a=3m/sec^2](https://tex.z-dn.net/?f=a%3D3m%2Fsec%5E2)
Time t =4.9 sec
We have to find the final velocity v
According to first law of motion v = u+at ,here v is the final velocity , a is acceleration and t is time
So ![v=5.13+3\times 4.9=19.83m/sec](https://tex.z-dn.net/?f=v%3D5.13%2B3%5Ctimes%204.9%3D19.83m%2Fsec)
So the final velocity is 19.83 m/sec