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3 years ago

Timers at a swim meet used four different clocks to time an event which recorded time is the most precise

Physics

2 answers:

tatiyna3 years ago

8 0

The answer is b 55.2 that is correct

Dennis_Churaev [7]3 years ago

4 0

Answer:

option D

Explanation:

the correct answer is option D

from the all four clocks the precise value will be given by the fourth clock which is 55.254 s.

because the measurement by that clock can be as small as 0.001 so, the precision of any instrument can be measured by how small value it can calculate so the answer will be option D

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when the force is halved, F₂ = 0.5F₁,

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$\frac{F_1}{m_1a_1} = \frac{0.5F_1}{2m_1a_2} \\\\2m_1a_2F_1 = 0.5F_1 m_1a_1\\\\2a_2 = 0.5a_1\\\\a_2 = \frac{0.5a_1}{2} = \frac{a_1}{2 \times 2} = \frac{a_1}{4} \\\\a_2 = \frac{1}{4} (a_1)$

Thus, If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)

when the force is doubled, F₂ = 2F₁,

mass is halved, m₂ = 0.5m₁

$\frac{F_1}{m_1 a_1} = \frac{2F_1}{0.5m_1 a_2} \\\\0.5m_1a_2 F_1 = 2F_1m_1a_1\\\\0.5a_2 = 2a_1\\\\a_2 = \frac{2a_1}{0.5} \\\\a_2 = 4(a_1)$

Thus, if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

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