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Step2247 [10]
3 years ago
13

A toy cannon uses a spring to project a 5.24-g soft rubber ball. The spring is originally compressed by 5.01 cm and has a force

constant of 8.08 N/m. When the cannon is fired, the ball moves 15.8 cm through the horizontal barrel of the cannon, and the barrel exerts a constant friction force of 0.031 0 N on the ball.With what speed does the projectile leave the barrel of the cannon?
Physics
1 answer:
salantis [7]3 years ago
7 0

Answer:

Speed will be equal to 1.40 m/sec

Explanation:

Mass of the rubber ball m = 5.24 kg = 0.00524 kg

Spring is compressed by 5.01 cm

So x = 5.01 cm = 0.0501 m

Spring constant k = 8.08 N/m

Frictional force f = 0.031 N

Distance moved by ball d = 15.8 cm = 0.158 m

Energy gained by spring

KE=\frac{1}{2}kx^2=\frac{1}{2}\times 8.08\times 0.0501^2=0.0101J

Energy lost due to friction

W=Fd=0.031\times 0.158=0.0048J

So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J

This energy will be kinetic energy

\frac{1}{2}mv^2=0.0052

\frac{1}{2}\times 0.00524\times v^2=0.0052

v = 1.40 m/sec

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A woman launches a boat from one shore of a straight river and wants to land at the point directly on the opposite shore. If the
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As water rises through the troposphere and cools, it changes from a(n) ————- to a(n) ———— through the process of condensation; w
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3 years ago
The density of gold is 19 300kg/m cube. what is the mass of gold cube with the length 0.2015m?
Sergeeva-Olga [200]

Answer:

157.9 kg

Explanation:

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From the question,

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make m the subject of the equation

m = Dv.................... Equation 2

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