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Juliette [100K]
3 years ago
15

Plz.... I cant do my hone work its maths... plz some one help me it has photo

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

4)

variables d and w

5d +1(4d)=36

9d=36

d=4       w=4x4=16

difference of price $12


5)

E  5 comics

F= 10

G=20

e+ (e+5) + 2(e+5)=35

e+ e+5 + 2e +10 =35

4e +15=35

4e=20

e=5

Eugene = 5 comics

6)

Agnes and Billy had each 300 (after drinking it will be less water)

A   300-200 =100

B  300-100  =200



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babunello [35]

Answer:

Apparently i cant see the photo im am so sorry but do need pints.

Step-by-step explanation:

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3 years ago
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Which factors is multiplied and give you 24 and when added gives you -4
klio [65]

Answer: the no.s are-

2.472

-6.472

Step-by-step explanation:

xy=24-----1

x+y=-4------2

from 2 we get x=-4-y

sustituting=

into 1 we get

quadratic eq = y^2 + 4y + 24=0

so

-4+- root 16-96/2

thus on further solving we get -2 +-4.472

on adding= -2+4.472= 2.472

on subtraction= -2 -4.472= -6.472

5 0
3 years ago
I got 15 points out of 20 what is my grade
sdas [7]

Answer:

75% (Letter grade = C)

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Samples of rejuvenated mitochondria are mutated (defective) in 1% of cases. Suppose 18 samples are studied, and they can be cons
Temka [501]

Probability that no samples are mutated is 0.83, probability that at most one sample is mutated is 0.9812 and probability that more than half the samples are mutated is 0.

Given percentage of rejuvenated mitochondria defective is 1%, and sample size is 18.

Binomial distribution is the probability of exactly x successes on n repeated trials and X can have two outcomes.

P(X=x)=C_{n,x} p^{x}(1-p)^{n-x}

percentage of defective rejuvendated mitochondria=1%

p=0.01

Sample size=18

n=18

a) No samples are mutated

This means P(X=0)=C_{18,0}(0.01)^{0} (0.99)^{18}

=0.83

b) At most one sample is mutated.

P(X<=1)=P(X=0)+P(X=1)

so,

P(X=0)=C_{18,0} (0.01)^{0}  (0.99)^{18}

=0.83

P(X=1)=C_{18,1}(0.01)^{1} (0.99)^{17}=

=0.1512

P(X<=1)=0.83+0.1512

=0.9812

c) More than half the samples are mutated.

P(X>9)=P(X=10)+P(X=11)+P(X=12)+P(X=13)+P(X=14)+P(X=15)+P(X=16)+P(X=17)+P(X=18)

Using two decimals digits precision all will be 0.

Hence Probability that no samples are mutated is 0.83, probability that at most one sample is mutated is 0.9812 and probability that more than half the samples are mutated is 0.

Learn more about probability at brainly.com/question/24756209

#SPJ4

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