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3 years ago

Which sentence describes a spontaneous redox reaction between two

Chemistry

1 answer:

Maurinko [17]3 years ago

8 0

Answer:

B. The element with the greater reduction potential is reduced :)

Explanation:

A P E X

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Butterflies like to drink the sweet nectar from flowers.

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3 years ago

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What happens to most of the Energy that an organism gets from consuming food? Help please

kobusy [5.1K]

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2 years ago

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1. What volume is required to contain 100.0 mol O2 at STP?

Colt1911 [192]

Answer:

The volume is 2238,6 L

Explanation:

We use the formula PV=nRT. The conditions STP are: 1 atm of pressure and 273K of temperature:

PV=nRT ---> V=(nRT)/P

V= 100 mol x 0,082 l atm/K mol x 273K/ 1 atm

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3 years ago

Assuming complete distribution, what is the molarity of 10 milligrams of lisinopril in 100 liters?

SVEN [57.7K]

Answer:

$2.47x10^{-7} M$

Explanation:

Lisoprisil's molecular mass is 405.488g/mol, we'll use this fact to calculate molarity, which units are mol/L, and we proceed to the calculus:

First, we'll unify unities, the 10 milligrams of lisinopril we'll transform into grams.

$10mg*\frac{1g}{1000mg}=0.01g$

Now that we have the same unities we'll calculate molarity using the molecular mass, the grams of lisinopril and the liters in which these grams are, let's consider that our final unities have to be mol/L.

$\frac{1mol}{405.488g}*\frac{0.01g}{100L}=2.47x10^{-7} M$

I hope you find this information useful and interesting! Good luck!

3 0

3 years ago

Calculate the EMF between copper and silver Ag+e-E=0.89v Cu=E=0.34v

bogdanovich [222]

Answer:

Depending on the $E^\circ$ value of $\rm Ag^{+} + e^{-} \to Ag\; (s)$ , the cell potential would be:

$0.55\; \rm V$ , using data from this particular question; or
approximately $0.46\; \rm V$ , using data from the CRC handbooks.

Explanation:

In this galvanic cell, the following two reactions are going on:

The conversion between $\rm Ag\; (s)$ and $\rm Ag^{+}$ ions, $\rm Ag^{+} + e^{-} \rightleftharpoons Ag\; (s)$ , and
The conversion between $\rm Cu\; (s)$ and $\rm Cu^{2+}$ ions, $\rm Cu^{2+}\; (aq) + 2\, e^{-} \rightleftharpoons \rm Cu\; (s)$ .

Note that the standard reduction potential of $\rm Ag^{+}$ ions to $\rm Ag\; (s)$ is higher than that of $\rm Cu^{2+}$ ions to $\rm Cu\; (s)$ . Alternatively, consider the fact that in the metal activity series, copper is more reactive than silver. Either way, the reaction is this cell will be spontaneous (and will generate a positive EMF) only if $\rm Ag^{+}$ ions are reduced while $\rm Cu\; (s)$ is oxidized.

Therefore:

The reduction reaction at the cathode will be: $\rm Ag^{+} + e^{-} \to Ag\; (s)$ . The standard cell potential of this reaction (according to this question) is $E(\text{cathode}) = 0.89\; \rm V$ . According to the 2012 CRC handbook, that value will be approximately $0.79\; \rm V$ .

The oxidation at the anode will be: $\rm Cu\; (s) \to \rm Cu^{2+} + 2\, e^{-}$ . According to this question, this reaction in the opposite direction ( $\rm Cu^{2+}\; (aq) + 2\, e^{-} \rightleftharpoons \rm Cu\; (s)$ ) has an electrode potential of $0.34\; \rm V$ . When that reaction is inverted, the electrode potential will also be inverted. Therefore, $E(\text{anode}) = -0.34\; \rm V$ .

The cell potential is the sum of the electrode potentials at the cathode and at the anode:

$\begin{aligned}E(\text{cell}) &= E(\text{cathode}) + E(\text{anode}) \\ &= 0.89 \; \rm V + (-0.34\; \rm V) = 0.55\; \rm V\end{aligned}$ .

Using data from the 1985 and 2012 CRC Handbook:

$\begin{aligned}E(\text{cell}) &= E(\text{cathode}) + E(\text{anode}) \\ &\approx 0.7996 \; \rm V + (-0.337\; \rm V) \approx 0.46\; \rm V\end{aligned}$ .

5 0

3 years ago