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2 years ago

What do all decomposition reactions have in common? (My answer: D, correct?)

2 answers:

5 0

"They start with one reactant and end with more than one product" is the answer. This is the representation of decomposition...

AB = A + B

Hope this helps and Mark Brainliest

inn [45]2 years ago

3 0

Correct answer is D.

,,They start with one reactant and end with more than one product."

:-) ;-)

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Buck's Turf Care Company mowed 233 lawns over a 11 week period. What is the average weekly rate of mowing lawns?

masya89 [10]

Answer: 21 lawns per week

Explanation:

The average weekly rate refers to how many lawns were mowed per week given that 233 were done in 11 weeks.

Rate will be given by;

= Lawns mowed / Weeks taken

= 233 / 11

= 21 lawns per week

6 0

3 years ago

Which of the following statements is true?

seropon [69]

Answer: option <span>D Chemical reaction rates vary with the conditions of the reaction, but nuclear decay rates do not.

Justification:

1) The rate of chemical reactions are affected by: concentration of the reactants, state of the reactants, temperature, and presence of catalizers. So the first part of the statement is true.

2) Nuclear decay rates are constant. The decay depends on the nature of the element but not the conditions. That is why dating fossils with radiactive isotopes is possible. So, the second part of the statement is true.
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5 0

3 years ago

Select the correct answer.

Illusion [34]

Answer: the new force will be 1/9 of the original force

Explanation: Please see attachment for explanation

5 0

2 years ago

NO2+H4➡2 H2O+N What are the elements

Firdavs [7]

They are nitrogen, oxygen, hydrogen

6 0

3 years ago

Read 2 more answers

CdF2(s)⇄Cd2+(aq)+2F−(aq)A saturated aqueous solution of CdF2 is prepared. The equilibrium in the solution is represented above.

kupik [55]

Answer:

The correct answer is option a.

Explanation:

$CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)$

Equilibrium concentration cadmium ions = $[Cd^{2+}]=0.0585 M$

Equilibrium concentration fluoride ions = $[F^{-}]=0.117 M$

Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.

The molar solubility of the solid cadmium fluoride = 0.0585 M

$CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)$ ..[1]

$NaF(s)\rightleftharpoons Na^{+}(aq)+F^-(aq)$

Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.

Hence, decrease in solubility will be observed.

8 0

2 years ago