Answer:
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Here we have to draw the mechanism of the reduction reaction between benzaldehyde and sodium borodeuteride to form the corresponding alcohol.
The reducing agent sodium borodeuteride can reduce the aldehydes to its corresponding alcohol. The reaction mechanism is shown in the attached image.
The reaction mechanism can be explained as-
The sodium borodeuteride is highly ionic in nature thus it remains as Na⁺ and BD₄⁻ The deuterium atom of BD₄⁻ attack the carbonyl carbon atom and substitute one of its deuterium as shown in the figure.
One molecule of sodium borodeuteride can reduce four molecules of benzaldehyde. The polar solvent like alcohol donates the proton as shown in the mechanism.
The converted alcohol contains the deuterium atom at the -C center. Thus benzaldehyde is converted to deuteroted benzyl alcohol.
The balanced equation for the reaction is as follows
C₆H₁₂O₆ + 6O₃ --> 6CO₂ + 6H₂O
stoichiometry of glucose to CO₂ is 1:6
when 1 mol of glucose reacts - 6 mol of CO₂ are formed
therefore when 5.87 mol of glucose reacts - 6 x 5.87 mol = 35.22 mol
therefore 35.2 mol of CO₂ is formed
Answer:
proton: positive
electron: negative
neutron: neutral
Looks like you already have it.
C. 2
2H_2O + <u>2e</u>^(-) → H_2 + 2OH^(-)
2Cl^(-) → Cl_2 + <u>2e</u>^(-)
2H_2O +Cl^(-) + <u>2e</u>^(-) → H_2 + Cl_2 + 2OH^(-) + 2e^(-)
2H_2O +2Cl^(-) → H_2 + Cl_2 + 2OH^(-)
This is a <em>redox reaction</em> in which two chloride ions transfer two electrons to two molecules of water.