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Maslowich
3 years ago
15

An arrow strikes a target moving at 75 m/s and embeds itself 15 cm into the target. If the arrow stopped with constant accelerat

ion, how long (in seconds) after striking the target did it take for the arrow to come to rest?
Physics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

Answer:

4 ms

Explanation:

initial velocity, u = 75 m/s

final velocity, v = 0

distance, s = 15 cm = 0.15 m

Let the acceleration is a and the time taken is t.

Use third equation of motion

v² = u² + 2 a s

0 = 75 x 75 - 2 a x 0.15

a = - 18750 m/s^2

Use first equation of motion

v = u + at

0 = 75 - 18750 x t

t = 4 x 10^-3 s

t = 4 ms

thus, the time taken is 4 ms.

Explanation:

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Light travels through a vacuum at a speed of 3 x 10 m/s. What is the speed of
Andrew [12]

Answer:

v = c / n      (n = 1 for air)

v = c / 1.33 = 3 * 10E8 m/s / 1.33 = 2.25 * 10E8 m/s

3 0
3 years ago
Which is an example of a scientist using a mathematical model to describe the weather?
mr Goodwill [35]

Answer:

The scientist finds an equation that predicts how long the rainstrom will last.

Explanation:

I just answered it :)

6 0
3 years ago
a teacher drives from school to the mall. then she goes to the doctors office for a physical examination. what is the magnitude
Amanda [17]

The magnitude of the teachers displacement is the difference between

the location of the school and the location of the doctors office

The reason behind the above expression are explained as follows

The known locations of the teacher;

Initial location; The school

Second location; The mall

The eventual location; The doctors office

The required information;

The magnitude of the teachers displacement

The method of obtaining the displacement of the teacher;

Qualitatively, the displacement of the teacher can be obtained by applying the definition of displacement as follows;

The definition of displacement is an object's change in position, given by the difference between its start and finish locations

According to the definition of displacement, therefore, the magnitude of

the teachers displacement is the distance between the school and the

doctors office which is given by the difference between the coordinates of

the location of the school and the location of the doctors office

The magnitude of the displacement of the teacher = The coordinate of the location of the doctors office - The coordinate of the location of the school

Learn more about displacement here;

brainly.com/question/17587058

5 0
3 years ago
In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.14 m. The mug
defon
Say the horizontal component of the velocity is vx and the vertical is vy.
Initially at t=0 (as the mug leaves the bar) the components are v0x and v0y.
Obviously (I hope!) v0y = 0.

The equations for horizontal and vertical projectile motion (with the positive direction up) are

x = x0 + v0x t
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2

Now choose the origin to be the end of the counter. x0=0 and y0=0. The equations simplify to

x = v0x t
y = - 1/2 g t^2

You know that x = 1.20m when y = -0.88m
From the y equation (and g=10 m/s^2) you can calculate the time that the mug hits the floor.
t = 0.420s
From the x equation we get the initial horizontal velocity
v0x = x/t = 1.2/0.42 = 2.86 m/s

(b) x-component of velocity is constant since there are no horizontal forces so vx = 2.86 m/s
y-component is given by v = u+at with u=0 and a=-g
vy = -gt = -4.2m/s

Now tan(angle) = vy/vx so angle = arctan(vy/vx)
7 0
3 years ago
Researchers at the University of Georgia have evaluated trends in streamside forests in areas within roughly 400 feet of the sta
Colt1911 [192]
<span>B: adds aesthetic value to the landscape. Think about it, out of all your options, that's the one that doesn't really help anything.

And I took the test, so take my word for it.</span>
6 0
3 years ago
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