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4 years ago

The rate of chemical reactions decreases as temperature is raised. true or false

Chemistry

2 answers:

krok68 [10]4 years ago

6 0

Answer:

False

Explanation:

For most reactions, raising the temperature leads to a faster reaction/higher rate of reaction. This is because a higher temperature means that the reactant particles have a higher average kinetic energy meaning more of them have enough activation energy needed to partake in a successful collision. Not only that because they have a higher average kinetic energy they are moving faster meaning more chances of collisions

asambeis [7]4 years ago

5 0

False, the rate of chemical reactions is increased due to the higher level of kinetic energy present <span />

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alina1380 [7]

Answer:

Explanation:

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3 years ago

For parts a & b below, derive only the initial value problem set up.

Otrada [13]

Answer:

Explanation:

From the given information:

Let y(t) be the amount of sugar in tank A at any time.

Then, the rate of change of sugar in the tank is given by:

$\dfrac{dy}{dt}= (rate \ in ) - ( rate \ out )$

The rate of the sugar coming into the tank is 0

$\text{rate of sugar going out }= \dfrac{y(t) \ pound}{100}\times \dfrac{1 }{min} \\ \\ = \dfrac{y}{100} \ pound/min$

$So; \\ \\ \\ \dfrac{dy}{dt} = 0 - \dfrac{y}{100} \\ \\ \implies \dfrac{dy}{y }= -\dfrac{dt}{100 } \\ \\ \implies dx|y| = -\dfrac{t}{100}+C \\ \\ \implies e*{In|y|}= e^{-\dfrac{t}{100}+C} \\ \\ \implies y = Ce^{-\dfrac{t}{100}}$

Initial amount of sugar = 25 Pounds

Now; y(0) = 25

25 = Ce⁰

C = 25

So; y(t) = 25 $e^{-\dfrac{t}{100}$

Thus, the amount of sugar at any time t = $\mathbf{25 e^{^{-\dfrac{t}{100}}}}$

B) For tank B :

$\dfrac{dy}{dt}= 1 - \dfrac{y}{50 } \\ \\ \dfrac{dy}{dt}= \dfrac{50-y}{50} \\ \\ \dfrac{dy}{50-y }= \dfrac{dt}{50}$

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3 years ago

What’s inside a cell that allow it to function and survive

mote1985 [20]

Cells have many structure inside of them called organelles which allow it to function and survive

Hope it helps

8 0

3 years ago

How many moles of carbonate ions are present in a sample that contains 1.35 moles of chromium (III) carbonate

charle [14.2K]

Answer:

According to the formula $Cr_{2} (CO_3)_3$ there are 3 moles of carbonate ions for every mole of the compound. so you would multiply 1.35 by 3 moles to get 4.05 moles of ions.

Explanation:

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4 years ago

Which of the following is most likely a heavier stable nucleus? (select all that apply) Select all that apply: A nucleus with a

irakobra [83]

The question is incomplete, the complete question is;

Which of the following is most likely a heavier stable nucleus? (select all that apply) Select all that apply: A nucleus with a neutron:proton ratio of 1.05 A nucleus with a A nucleus with a neutron:proton ratio of 1.49 The nucleus of Sb-123 A nucleus with a mass of 187 and an atomic number of 75

Answer:

A nucleus with a A nucleus with a neutron:proton ratio of 1.49

A nucleus with a mass of 187 and an atomic number of 75

Explanation:

The stability of a nucleus depends on the number of neutrons and protons present in the nucleus. For many low atomic number elements, the number of protons and number of neutrons are equal. This implies that the neutron/proton ratio = 1

Elements with higher atomic number tend to be more stable if they have a slight excess of neutrons as this reduces the repulsion between protons.

Generally, the belt of stability for chemical elements lie between and N/P ratio of 1 to an N/P ratio of 1.5.

Two options selected have an N/P ratio of 1.49 hence they are heavy stable elements.

5 0

4 years ago