Answer:
88750 N
Explanation:
given data:
plastic deformation σy=266 MPa=266*10^6 N/m^2
cross-sectional area Ao=333 mm^2=333*10^-6 m^2
solution:
To determine the maximum load that can be applied without
plastic deformation (Fy).
Fy=σy*Ao
=88750 N
Answer:
(a) attached below
(b)
![lagging](https://tex.z-dn.net/?f=lagging)
(c) ![I_{C} =32.37 A](https://tex.z-dn.net/?f=I_%7BC%7D%20%3D32.37%20A)
(d)
Ω
(e)
and ![I_{line} =27.66 A](https://tex.z-dn.net/?f=I_%7Bline%7D%20%3D27.66%20A)
Explanation:
Given data:
![P_{1}=15 kW](https://tex.z-dn.net/?f=P_%7B1%7D%3D15%20kW)
![S_{2} =10 kVA](https://tex.z-dn.net/?f=S_%7B2%7D%20%3D10%20kVA)
![lagging](https://tex.z-dn.net/?f=lagging)
![leading](https://tex.z-dn.net/?f=leading)
![Volts](https://tex.z-dn.net/?f=Volts)
(a) Draw the power triangle for each load and for the combined load.
°
°
≅ ![20kVAR](https://tex.z-dn.net/?f=20kVAR)
![P_{2} =S_{2}*pf_{2} =10*0.8=8 kW](https://tex.z-dn.net/?f=P_%7B2%7D%20%3DS_%7B2%7D%2Apf_%7B2%7D%20%3D10%2A0.8%3D8%20kW)
≅ ![-6 kVAR](https://tex.z-dn.net/?f=-6%20kVAR)
The negative sign means that the load 2 is providing reactive power rather than consuming
Then the combined load will be
![P_{c} =P_{1} +P_{2} =15+8=23 kW](https://tex.z-dn.net/?f=P_%7Bc%7D%20%3DP_%7B1%7D%20%2BP_%7B2%7D%20%3D15%2B8%3D23%20kW)
![Q_{c} =Q_{1} +Q_{2} =20-6=14 kVAR](https://tex.z-dn.net/?f=Q_%7Bc%7D%20%3DQ_%7B1%7D%20%2BQ_%7B2%7D%20%3D20-6%3D14%20kVAR)
(b) Determine the power factor of the combined load and state whether lagging or leading.
![S_{c} =P_{c} +jQ_{c} =23+14j](https://tex.z-dn.net/?f=S_%7Bc%7D%20%3DP_%7Bc%7D%20%2BjQ_%7Bc%7D%20%3D23%2B14j)
or in the polar form
°
![lagging](https://tex.z-dn.net/?f=lagging)
The relationship between Apparent power S and Current I is
![S=VI^{*}](https://tex.z-dn.net/?f=S%3DVI%5E%7B%2A%7D)
Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.
(c) Determine the magnitude of the line current from the source.
Current of the combined load can be found by
![I_{C} =S_{C}/\sqrt{3}*V](https://tex.z-dn.net/?f=I_%7BC%7D%20%3DS_%7BC%7D%2F%5Csqrt%7B3%7D%2AV)
![I_{C} =26.92*10^3/\sqrt{3}*480=32.37 A](https://tex.z-dn.net/?f=I_%7BC%7D%20%3D26.92%2A10%5E3%2F%5Csqrt%7B3%7D%2A480%3D32.37%20A)
(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω
![Q_{C} =3*V^2/X_{C}](https://tex.z-dn.net/?f=Q_%7BC%7D%20%3D3%2AV%5E2%2FX_%7BC%7D)
![X_{C} =3*V^2/Q_{C}](https://tex.z-dn.net/?f=X_%7BC%7D%20%3D3%2AV%5E2%2FQ_%7BC%7D)
Ω
(e) Compute the magnitude of the current in each capacitor and the line current from the source.
Current flowing in the capacitor is
![I_{cap} =V/X_{C} =480/49.37=9.72 A](https://tex.z-dn.net/?f=I_%7Bcap%7D%20%3DV%2FX_%7BC%7D%20%3D480%2F49.37%3D9.72%20A)
Line current flowing from the source is
![I_{line} =P_{C} /3*V=23*10^3/3*480=27.66 A](https://tex.z-dn.net/?f=I_%7Bline%7D%20%3DP_%7BC%7D%20%2F3%2AV%3D23%2A10%5E3%2F3%2A480%3D27.66%20A)
Answer: Solid state welding
Explanation: Solid state welding is the welding procedure which is based on the temperatures and pressure but without any liquid or vapor as aid for welding.This process is carried mainly cohesive forces and considering forces as less important. Brazing,soldering and adhesive is the process in which material are joint which the help of solid welding agent.Thus solid state welding is the correct option.
The number of hectares of each crop he should plant are; 250 hectares of Corn, 500 hectares of Wheat and 450 hectares of soybeans
<h3>How to solve algebra word problem?</h3>
He grows corn, wheat and soya beans on the farm of 1200 hectares. Thus;
C + W + S = 12 ----(1)
It costs $45 per hectare to grow corn, $60 to grow wheat, and $50 to grow soybeans. Thus;
45C + 60W + 50S = 63750 -----(2)
He will grow twice as many hectares of wheat as corn. Thus;
W = 2C ------(3)
Put 2C for W in eq 1 and eq 2 to get;
C + 2C + S = 1200
3C + S = 1200 -----(4)
45C + 60(2C) + 50S = 63750
45C + 120C + 50S = 63750
165C + 50S = 63750 ------(5)
Solving eq 4 and 5 simultaneosly gives;
C = 250 and W = 500
Thus; S = 1200 - 3(250)
S = 450
Read more about algebra word problems at; brainly.com/question/13818690
Answer:
diesel engine
Explanation:
because diesel is stronger than petrol