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Nesterboy [21]
2 years ago
8

Need help on this really bad!

Chemistry
1 answer:
timofeeve [1]2 years ago
7 0

Answer:

Help your self

Explanation:

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If you want to prepare 80.0 mL of 4.00M acid ,How many mL of 12.4 M HCl are required ?
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M_{A}V_{A}=M_{B}V_{B}\\(80.0)(4.00)=V_{B}(12.4)\\V_{B}=\frac{(80.0)(4.00)}{12.4} \approx \boxed{25.8 \text{ mL}}

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3 years ago
How many grams of n2f4 can be produced from 225g f2?
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The answer is 615.91 grams of <span>n2f4

Solution:
225g F2 x [(1molF2)/(38gramsF2)] x [</span>(1molF2)/(1molN2F4)] x [(104.02 grams N2F4)/(1molN2F4)]
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