Answer:
b.) 25 ml of aluminum hydroxide
Explanation:
For this question, we have to assume that we have the <u>same concentration</u> for all the solutions, for example, <u>1 M</u>. Additionally, we have to take into account the <u>ionization reaction</u> for each species:
a)
<u>we have to ions</u>
b)
<u>we have fourth ions</u>
c)
<u>we have two ions</u>
d)
<u>we have one ion</u>
If we have the same volume and the same concentration the variables that will help us to answer the question would be the n<u>umber of ions.</u> If we have <u>more ions we will have more particles dissolved</u>. Therefore the answer would be b) (<u>due to the fourth ions</u>).
I hope it helps
Answer:
the new volume would be 1.62 L
Explanation:
stp is 0 degrees C or 273.15 K and 1atm for the pressure
22 degrees C is 295.15 K
use the combined gas law formula and solve for v2
v2=p1(v1)(t2)/p2(t1)
v2=1atm(1.2L)(295.15)/0.8atm(273.15K)
v2=1.62
Answer:
Covalent bond
Explanation:
(pls give me brainliest) <3
Answer is: C. H3PO4, phosphoric acid.
A) HClO₂ is chlorous acid.
Chlorous acid is weak inorganic acid. In this acid, chlorine has oxidation number +3.
B) HNO₂ is nitrous acid.
Nitrous acid is a weak monobasic acid. In this acid, nitrogen has oxidation number +3.
D) HI is hydroiodic acid.
Hydroiodic acid is a highly acidic aqueous solution of hydrogen iodide. In this acid, iodine has oxidation number -1.
Answer:
Percent error = 3.7%
Explanation:
Given data:
Density of Al cylinder = ?
Weight of cylinder = 18 g
Diameter = 1.3 cm
Height = 5.2 cm
Actual density of Al = 2.7 g/cm³
Percent error = ?
Solution:
First of all we will calculate the volume of cylinder through given formula.
V = πr²h
r = diameter /2
V = 22/7 × (0.65 cm)²× 5.2 cm
V = 22/7 × 0.4225cm²× 5.2 cm
V = 6.89 cm³
Now we will calculate the density.
d = m/v
d = 18 g/ 6.89 cm³
d = 2.6 g/cm³
Percent error:
Percent error = measured value - actual value /actual value × 100
Percent error = 2.6g/cm³ - 2.7g/cm³ /2.7g/cm³ × 100
Percent error = 3.7%
Negative sign shows that measured or experimental value is less than actual value.