Answer:
ºC
Explanation:
We have to start with the variables of the problem:
Mass of water = 60 g
Mass of gold = 13.5 g
Initial temperature of water= 19 ºC
Final temperature of water= 20 ºC
<u>Initial temperature of gold= Unknow</u>
Final temperature of gold= 20 ºC
Specific heat of gold = 0.13J/gºC
Specific heat of water = 4.186 J/g°C
Now if we remember the <u>heat equation</u>:


We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

Now we can <u>put the values into the equation</u>:

Now we can <u>solve for the initial temperature of gold</u>, so:

ºC
I hope it helps!
(46.972* 69.472% + 48.961*21.667% + <span>49.954*8.8610%)/100% =
</span>= 46.972* 0.69472 + 48.961*0.21667 + 49.954*0.088610 =47.667 u
Answer:
pls the image didn't come
Explanation:
ols the. atom's image didn't appear
Decrease because loss of electrons.