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topjm [15]
3 years ago
10

Which type of hybridization leads to a bent molecular geometry and a tetrahedral electron domain geometry? sp s2p s2p2 sp3

Chemistry
2 answers:
Setler [38]3 years ago
7 0
Your answer is going to be sp3. :)
Orlov [11]3 years ago
3 0

Answer is: sp3 hybridization.

Water (H₂O), oxygen difluoride (OF₂) and sulfur(IV) oxide (SO₂) are examples of bent molecules.

Oxygen atom in water molecule has sp3 hybridization. The bond angle between the two hydrogen atoms is approximately 104.45°.

Water is polar because of the bent shape of the molecule.

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Answer:

The correct answer is "a quote from Mein Kampf written by Adolf Hitler".

Explanation:

Mein Kampf is a 1925 famous book written by Adolf Hitler that serves as an autobiographical manifesto of the Nazi Party that he led. The statement that is included in this paragraph belongs to a quote of this book. In this statement it is reflected the ideology of Adolf Hitler, denying democracy as a government and expressing its ideology of a totalitarian autocracy.

5 0
3 years ago
PLEASE HELP ASAP!!!!!
arsen [322]

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2 years ago
The Earth's circumference around the equator is slightly bulged as compared to the circumference around the poles. if the circum
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The earth in m is 510
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3 years ago
Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac
GalinKa [24]
<h2>a) The rate at which NO_2 is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen O_2 is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of NO = -\frac{1d[NO]}{2dt} = 0.066 M/s

Rate in terms of disappearance of O_2 = -\frac{1d[O_2]}{dt}

Rate in terms of appearance of NO_2= \frac{1d[NO_2]}{2dt}

1. The rate of formation of NO_2

-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}

\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s

2. The rate of disappearance of O_2

-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}

-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s

Learn more about rate law

brainly.com/question/13019661

https://brainly.in/question/1297322

7 0
3 years ago
10.0 grams of water are heated during the preparation of a cup of coffee 1.0x 103 j of the heat are added to the water. which is
katovenus [111]

<u>Answer:</u> The final temperature of the coffee is 43.9°C

<u>Explanation:</u>

To calculate the final temperature, we use the equation:

q=mC(T_2-T_1)

where,

q = heat released = 1.0\times 10^3J=1000J

m = mass of water = 10.0 grams

C = specific heat capacity of water = 4.184 J/g°C

T_2 = final temperature = ?

T_1 = initial temperature = 20°C

Putting values in above equation, we get:

1000J=10.0g\times 4.184J/g^oC\times (T_2-20)\\\\T_2=43.9^oC

Hence, the final temperature of the coffee is 43.9°C

6 0
3 years ago
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