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mihalych1998 [28]
3 years ago
14

A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 790.5 meters from the wall and the sound of h

er voice travels at 329.2 m/s at that location. How long after she shouts will she hear her echo? Round to two decimals. (Be careful to consider why echoes happen)
Physics
1 answer:
tester [92]3 years ago
7 0

Answer:

4.80 seconds

Explanation:

The velocity of sound is obtained from;

V= 2d/t

Where;

V= velocity of sound = 329.2 ms-1

d= distance from the wall = 790.5 m

t= time = the unknown

t= 2d/V

t= 2 × 790.5/ 329.2

t= 4.80 seconds

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Explanation:

Area of rectangular field, A = 830 ft²

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                    l=\frac{830}{w}

Fencing costs $2 per foot for two opposite sides, and $3 per foot for the other two sides.

            Cost for fencing, C = 2 x 2 x w + 3 x 2 x l = 4 w + 6 l

             C=4w+6\times \frac{830}{w}

For minimum cost we have derivative is zero

           dC=4\times dw-6\times \frac{830}{w^2}\times dw\\\\0=4\times dw-6\times \frac{830}{w^2}\times dw\\\\w^2=1245\\\\w=32.45ft\\\\lw=830\\\\l\times 32.45=830\\\\l=23.52ft

Dimension for cheap enclose = 32.45 ft x 23.52 ft

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2 years ago
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Explanation:

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