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Vera_Pavlovna [14]
3 years ago
8

A 0.40-kg object is traveling to the right (in the positive direction) with a speed of 4.0 m/s. After a 0.20 s collision, the ob

ject is traveling to the left at 2.0 m/s. What is the magnitude of the impulse (in N-s) acting on the object
Physics
1 answer:
Sav [38]3 years ago
8 0

Answer:

2.4 N\cdot s.

Explanation:

The equation that models the travel of the object is:

m \cdot v{o} + \Sigma F \cdot \Delta t = m \cdot v_{f}

The impulse is:

\Sigma F \cdot \Delta t = m \cdot (v_{f} - v_{o})

By replacing terms:

\Sigma F \cdot \Delta t = (0.40 kg) \cdot [- 2 \frac{m}{s} - 4 \frac{m}{s} ]\\\Sigma F \cdot \Delta t = - 2.4 N \cdot s

The magnitude of the impulse acting on the object is 2.4 N\cdot s.

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8459299
sergeinik [125]

Answer:

Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy

3 0
2 years ago
How far should the second antenna be moved in order to receive a minimum signal from a station that broadcasts at 99.4 MHz?
raketka [301]

Answer:

So the distance of the antenna from the station will be 3.018 m

Explanation:

We have given the frequency of the broadcast f=99.4MHz=99.4\times 10^4Hz

The speed of light c=3\times 10^8m/sec

The distance of the antenna to receive a minimum signal from the station is given by d=\frac{v}{f}=\frac{3\times 10^{8}}{99.4\times 10^6}=3.018m

So the distance of the antenna from the station will be 3.018 m

5 0
3 years ago
) what is kinetic energy, and how does it differ from potential energy?
tankabanditka [31]
 Kinetic energy<span>is the </span>energy<span> of body or a system with respect to the motion of the body or of the particles in the system. </span>Potential energy<span> is the stored </span>energy<span> in an object of system because of its position or configuration.</span>
7 0
3 years ago
What is tan(16°)?<br><br> A. 0.96<br> B.0.16<br> C.0.39<br> D.0.29
Alex Ar [27]

Answer:

D. 0.29

Explanation:

5 0
3 years ago
) By observing that the centripetal acceleration of the Moon around the Earth is ac = 2.7 × 10-3 m/s2, what is the gravitatonal
Sedbober [7]

Answer:

G = 6,786 10⁻¹¹ m³ / s² kg

Explanation:

The law of universal gravitation is

         F = G m M/ r²

Where G is the gravitational constant, m and M are the masses of the bodies and r is the distance from their centers

Let's use Newton's second law

         F = m a

The acceleration is centripetal

          a = a_{c}  

We replace

         G m M / r² = m  a_{c}  

         G =  a_{c}   r² / M

Let's replace and calculate

         G = 2.7 10⁻³ (3.88 10⁸)² / 5.99 10²⁴

         G = 6,786 10⁻¹¹ m³ / s² kg

Let's perform a dimensional analysis

[N m²/kg²] = [kg m/s²   m² / kg²] = [m³ / s² kg]

4 0
3 years ago
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