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tensa zangetsu [6.8K]
3 years ago
6

At a particular instant the magnitude of the momentum of a planet is 2.05 × 10^29 kg·m/s, and the force exerted on it by the sta

r it is orbiting is 3.0 × 10^23 N. The angle between the planet's momentum and the gravitational force exerted by the star is 63°.
What is the parallel component of the force on the planet by the star?
Physics
1 answer:
Evgesh-ka [11]3 years ago
3 0
727.5256266 AWNSERrRrrRr
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We tend to feel less _____ when more people are around to help out. compassionate conformity responsible no answer is correct
never [62]
Responsible  because we feel less stressed when others help out with our responsibilities. 
               
                 
5 0
4 years ago
What is the effect on the force of gravity between two objects if the mass of one object remains unchanged while the distance to
drek231 [11]

Answer:

The force of gravity after you double the mass and the distance is half of the initial force: F_{2}=\frac{1}{2}F_{1}

Explanation:

The initial force of gravity is:

F_{1}=\frac{Gm_{1}m_{2}}{r^2}

where G is the universal gravitational constant, m_{1} is the mass of the first object, m_{2} is the mass of the second object, and r is the distance between the objects.

If the mass of the second object is doubled, now we have 2m_{2}, and if the distance between the objects is also doubled instead of r now we have 2r.

So the force of gravity now is:

F_{2}=\frac{Gm_{1}(2m_{2})}{(2r)^2}\\ F_{2}=\frac{2Gm_{1}m_{2}}{4r^2} \\F_{2}=\frac{1}{2} \frac{Gm_{1}m_{2}}{r^2}

and we know that F_{1}=\frac{Gm_{1}m_{2}}{r^2}

so the new force of gravity is:

F_{2}=\frac{1}{2}F_{1}

The force of gravity after you double the mass and the distance is half of the initial force.

3 0
3 years ago
Calculate the effective radiation dosage in sieverts for a 57 57 ‑kg person who is exposed to 4.2 × 10 9 4.2×109 particles of al
Rus_ich [418]

Answer:

  Dose = 5.4 10⁻⁴  Sv

Explanation:

The radiation dose absorbed by the body is 81% of the incident radiation, which is the number of particles per energy of each particle

    E = 0.81 n₀ E₀

    E = 0.81 4.2 10⁹ 0.81 6.1 10⁻¹³

    E = 2.075 10⁻³ J

Effective radiation dose

     Dose1 = n x RBE

     Dose1 = 2,075 10⁻³ 15

     Dose1 = 3.1 10⁻² REM

The effective radiation dose in sievert

          Dose = dose1 / m

          Dose = 3.1 10⁻² / 57

          Dose = 5.4 10⁻⁴      [j / kg]

          Dose = 5.4 10⁻⁴  Sv

6 0
4 years ago
What units would you use to measure time that has elapsed?
dedylja [7]
You would use seconds as seconds is a unit of time
6 0
3 years ago
A deer is running from a mountain lion when it encounters a fence that is 1.50 m high. Seeing the fence, the deer jumps, leaving
Novosadov [1.4K]

Answer:

Explanation:

Given

Initial Velocity (u)=13 m/s

angle=29^{\circ}

distance between fence and deer=2.5 m

We consider deer jump similar to projectile motion

equation of trajectory

y=xtan\theta -\frac{gx^2}{2u^2(cos\theta )^2}

y=2.5tan(29)-\frac{9.8\times 2.5^2}{2\times 13^2\times (cos29)^2}

y=1.385-0.2368=1.148 m

Thus deer will cross the fence with an difference in its jump and fence

1.5-1.148=0.351 m

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{13^2\times (sin29)^2}{2\times 9.8}

h_{max}=2.02 m

so deer rises during when it is over fence

8 0
4 years ago
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