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tensa zangetsu [6.8K]
3 years ago
6

At a particular instant the magnitude of the momentum of a planet is 2.05 × 10^29 kg·m/s, and the force exerted on it by the sta

r it is orbiting is 3.0 × 10^23 N. The angle between the planet's momentum and the gravitational force exerted by the star is 63°.
What is the parallel component of the force on the planet by the star?
Physics
1 answer:
Evgesh-ka [11]3 years ago
3 0
727.5256266 AWNSERrRrrRr
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Ampres law is often written contourintegral B vector (r vector) middot dl vector = mu_0I_enclosed. The integral on the left is
uranmaximum [27]

Answer:

(C) line integral along a closed loop

This integral is evaluated by dividing the path into infinitesimal segments dL, calculating the scalar product B•dL for each segment, and sum these products. The component of B parallel to dL at each point is always used in evaluating this integral.

The line integral is equal to mu_o × I.

Explanation:

4 0
3 years ago
Review. (b) What is the mass difference?
nignag [31]

The mass difference is in between the two is equivalent to the binding energy of the nucleus .

<h3>What is meant by mass difference? </h3>

Δm be the mass difference is defined as the difference between the mass of the nucleus and the total mass of the individual nucleons that comprise it.

Binding energy is the energy required to split the nucleus of an atom into neutrons and protons, while mass defect is the difference between the predicted mass and the actual mass of the nucleus of an atom .

The mass difference is difference between the mass of nucleus and the Total mass of the individual nucleons that make it up.

∆m = final mass - initial mass.

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brainly.com/question/19694949

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8 0
1 year ago
A thin rod (length = 2.97 m) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge.
nlexa [21]

Answer:

a)  w = 2.57 rad / s , b)   α = 3.3 rad / s²

Explanation:

a) Let's use the conservation of mechanical energy, we will write it in two points the highest and when touching the ground

Initial. Higher

       Em₀ = U = m g h

Final. Touching the ground

       Em_{f} = K = ½ I w²

How energy is conserved

       Em₀ = Em_{f}

       mg h = ½ I w2

The moment of specific object inertia

        I = m L²

We replace

       m g h = ½ (mL²) w²

       w² = 2g h / L²

The height of the object is the length of the bar

        h = L

        w = √ 2g / L

       w = √ (2 9.8 / 2.97)

       w = 2.57 rad / s

b) the angular acceleration can be found from Newton's second rotational law

       τ = I α

       W L = I α

       mg L = (m L²) α

       α = g / L

       α = 9.8 / 2.97

       α = 3.3 rad / s²

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3 years ago
A ray of yellow light ( f8= 5.09 × 1014 Hz) travels at a speed of 2.04×10 meters per second in
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The complete question in the attached figure
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v ------------------- > is the speed in medium
n ------------------- > is the refractive index of medium
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It is a barred spiral galaxy.
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