Answer:
(C) line integral along a closed loop
This integral is evaluated by dividing the path into infinitesimal segments dL, calculating the scalar product B•dL for each segment, and sum these products. The component of B parallel to dL at each point is always used in evaluating this integral.
The line integral is equal to mu_o × I.
Explanation:
The mass difference is in between the two is equivalent to the binding energy of the nucleus .
<h3>What is meant by mass difference? </h3>
Δm be the mass difference is defined as the difference between the mass of the nucleus and the total mass of the individual nucleons that comprise it.
Binding energy is the energy required to split the nucleus of an atom into neutrons and protons, while mass defect is the difference between the predicted mass and the actual mass of the nucleus of an atom .
The mass difference is difference between the mass of nucleus and the Total mass of the individual nucleons that make it up.
∆m = final mass - initial mass.
To learn more about mass refer to:
brainly.com/question/19694949
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Answer:
a) w = 2.57 rad / s
, b) α = 3.3 rad / s²
Explanation:
a) Let's use the conservation of mechanical energy, we will write it in two points the highest and when touching the ground
Initial. Higher
Em₀ = U = m g h
Final. Touching the ground
= K = ½ I w²
How energy is conserved
Em₀ =
mg h = ½ I w2
The moment of specific object inertia
I = m L²
We replace
m g h = ½ (mL²) w²
w² = 2g h / L²
The height of the object is the length of the bar
h = L
w = √ 2g / L
w = √ (2 9.8 / 2.97)
w = 2.57 rad / s
b) the angular acceleration can be found from Newton's second rotational law
τ = I α
W L = I α
mg L = (m L²) α
α = g / L
α = 9.8 / 2.97
α = 3.3 rad / s²
The complete question in the attached figure
Let
c ------------------- > is the speed of light
v ------------------- > is the speed in medium
n ------------------- > is the refractive index of medium
we know that
c/v = n
n = (3 x 10^8)/(2.04 x 10^8) = 1.47
1.47 is the refractive index of glycerol.
therefore
the answer is (4) glycerol
It is a barred spiral galaxy.