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trapecia [35]
2 years ago
9

What is the speed of an object at rest? a. 0.0 m/s c. 9.8 m/s b. 1.0 m/s d. 9.81 m/s

Physics
1 answer:
pishuonlain [190]2 years ago
8 0
Answer:

A 0.0 m/s

An object at rear is not moving so it is morning 0m every second.
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A baseball is batted from a height of 1.09 m with a speed of
kobusy [5.1K]

(a) The horizontal and vertical components of the ball’s initial velocity is 37.8 m/s and 12.14 m/s respectively.

(b) The maximum height above the ground reached by the ball is 8.6 m.

(c) The distance off course the ball would be carried is 0.38 m.

(d) The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

<h3>Horizontal and vertical components of the ball's velocity</h3>

Vx = Vcosθ

Vx = 39.7 x cos(17.8)

Vx = 37.8 m/s

Vy = Vsin(θ)

Vy = 39.7 x sin(17.8)

Vy = 12.14 m/s

<h3>Maximum height reached by the ball</h3>

H = \frac{v^2 sin^2(\theta)}{2g} \\\\H = \frac{(39.7)^2 \times (sin17.8)^2}{2(9.8)} \\\\H = 7.51 \ m

Maximum height above ground = 7.51 + 1.09 = 8.6 m

<h3>Distance off course after 2 second </h3>

Upward speed of the ball after 2 seconds, V = V₀y - gt

Vy = 12.14 - (2x 9.8)

Vy = - 7.46 m/s

Horizontal velocity will be constant = 37.8 m/s

Resultant speed of the ball after 2 seconds = √(Vy² + Vx²)

V = \sqrt{(-7.46)^2 + (37.8)^2} \\\\V = 38.53 \ m/s

<h3>Resultant speed of the ball and crosswind</h3>

V = \sqrt{38.52^2 + 4^2} \\\\V = 38.72 \ m/s

<h3>Distance off course the ball would be carried</h3>

d = Δvt = (38.72 - 38.53) x 2

d = 0.38 m

The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

Learn more about projectiles here: brainly.com/question/11049671

5 0
2 years ago
) Un círculo de 120 cm de radio gira a 600 rpm. Calcula: a) su velocidad angular
DIA [1.3K]

Responder:

20πrads ^ -1; 24πrads ^ -1; 0,1 seg; 10 Hz

Explicación:

Dado lo siguiente:

Radio (r) del círculo = 120 cm

600 revoluciones por minuto en radianes por segundo

(600 / min) * (2π rad / 1 rev) * (1min / 60seg)

(1200πrad / 60sec) = 20π rad ^ -1

Velocidad angular (w) = 20πrads ^ -1

Velocidad lineal = radio (r) * velocidad angular (w)

Velocidad lineal = (120/100) * 20πrad

Velocidad lineal = 1.2 * 20πrads ^ -1 = 24πrads ^ -1

C.) Período (T):

T = 2π / w = 2π / 20π = 0.1 seg

D.) Frecuencia (f):

f = 1 / T = 1 / 0.1

1 / 0,1 = 10 Hz

5 0
3 years ago
Continue taking reading until the water starts to be boil​
Delicious77 [7]

Answer:

pogggs

Explanation:

4 0
3 years ago
Cells are the basic building block that makes up all living things. Cells are microscopic. What does this mean?
Archy [21]

Answer:

microscopic means that they are very very tiny, you cannot see them with the human eye, you have to use a tool like a microscope

Explanation:

6 0
3 years ago
Read 2 more answers
Una tortuga recorre una pista de 1,25 km que tiempo emplearia si lleara una velocidad de 0,2 km/h
Marina86 [1]

Responder:

<h2>5 horas </h2>

Explicación:

La velocidad se define como el cambio de distancia de un cuerpo con respecto al tiempo. Matemáticamente, Velocidad = Distancia / Tiempo

Dada la velocidad del coche = 0,25 km / hy la distancia = 1,25 km

El tiempo se expresa a partir de la fórmula como Tiempo = Distancia / Velocidad

La sustitución de los valores dados en la fórmula dará;

Tiempo = 1,25 km / 0,25 km / h

Tiempo = 5 horas

Por lo tanto, la tortuga tardará 5 horas en viajar a una velocidad de 0,2 km / h.

7 0
3 years ago
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