Answer:
See below
Explanation:
KE = 1/2 m v^2 multiply both sides by 2
2 (KE) = mv^2 divide both sides by m
2(KE) / m = v^2 sqrt both sides
√ [(2KE)/m ] = v
Answer:2t
Explanation:
Given
Jason throwing watermelon at speed v and it spend t time in air
time to reach max height
0=v-gt'
and time to reach bottom is also t'
t=2t'
For guy throws his watermelon at speed 2v
So total time in air will be
t''=2t
Answer:4s^-1
Explanation:Tangential Acceleration=v^2/r=(20)²/100=400/100
Answer:
28 cm and 32 cm
Explanation:
1. The spring pendulum hangs vertically, oscillates harmonic with amplitude 2cm and angular frequency 20 rad/s. The natural length of
a spring is 30cm. What is the minimum and maximum length of the spring during the oscillation? Take g = 10m/s2.
As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.
So, the minimum length is 28 cm and the maximum length is 32 cm.
