Answer:
The pressure at point 2 is 
Explanation:
From the question we are told that
The speed at point 1 is 
The gauge pressure at point 1 is 
The density of water is 
Let the height at point 1 be 
then the height at point two will be
Let the diameter at point 1 be 
then the diameter at point two will be
Now the continuity equation is mathematically represented as
Here 
are the area at point 1 and 2
Now given that the are is directly proportional to the square of the diameter [i.e 
]
which can represent as
=> 
where c is a constant
so 
=> 
=> 
Now from the continuity equation
=> 
=> 
Generally the Bernoulli equation is mathematically represented as
So
=> 
substituting values
Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC = 
Q' = + 42 nC = 
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:
Now,
Electric field at the mid-point due to charge Q' is given by:
Now,
The net Electric field is given by:
The gap between the two flasks is partially evacuated of air creating a near vacuum which significantly reduces heat transfer by conduction or convection
Answer:
= 5.1 W
Explanation:
time (t) = 30 ms = 0.03 s
mass (m) = 560 g = 0.56 kg
initial velocity (U) = 0 m/s
final velocity (V) = 0.74 m/s
power = \frac{work done}{t} = \frac{f x d}{t} = f x v = m x a x v
m x a x v = m x \frac{V-U}{t} x \frac{V + U}{2}
m x \frac{V-U}{t} x \frac{V + U}{2} = 0.56 x \frac{0.74 - 0}{0.03} x \frac{0.74+0}{2}
= 5.1 W
(2.5,-1) There you go bro
