For example, if it takes 15 hours to travel 900 miles. How many miles will you travel in one hour?
2 answers:
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Answer:
0.6844 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $1,250
Standard Deviation, σ = $125
We are given that the distribution of daily sales is a bell like shaped distribution that is a normal distribution.
Formula:
We have to find
P(sales less than $1,310)
Calculation the value from standard normal z table, we have,
0.6844 is the probability that sales on a given day at this store are less than $1,310.
Answer:
C. 13
Step-by-step explanation:
from on online source, the question should be placed as thus:
Of the following integers, which is the closest approximation to (√2 + √5)^2 ?
A. 7
B. 10
C. 13
D. 15
E. 17
This is known as Algebraic expression. So we have to expand to simplify further
using this identity th (a+b)^2 = a^2 + b^2 +2ab
(√2 + √5)^2 =
(√2 + √5)(√2 + √5)
................Expansion of the above
2 + 5 + 2√10
~ 2 +5 + 2(3)
C. 13
Answer:
a) NORM.S.INV(0.975)
Step-by-step explanation:
1) Some definitions
The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.
NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"
The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.
2) Solution for the problem
Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".
We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.
So for this case the correct function to use is: NORM.S.INV(0.975)
And the result after use this function is 1.96. And we can check the answer if we look the picture attached.
