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Alexandra [31]
3 years ago
14

While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.1 km away from the ac

tors. If the speed of sound through solid rock is 3000 m/s on average, the actors will feel the explosion before they hear it. How much time will pass between when they feel the explosion and when they hear it?
Physics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

The time that will pass between the feeling and hearing the explosion is 2,86 secs

Explanation:

First, let's calculate the time that the wave takes to travel until the actors feel the explosion:

1,1 km*\frac{1.000 mts}{1 km} *\frac{sec}{3.000 mts} = 0,37 secs

Now, the time that pass while the actors hear the sound is:

<em>(Remember that the sound speed in the air is 340 m/s on average)</em>

1,1 km * \frac{1.000 mts}{1 km} * \frac{sec}{340 mts} = 3,23 secs

So, the time between the feeling and hearing is 3,23 - 0,37 = 2,86 secs

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So your question actually says:

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What requirement must a force acting on a object satisfy in order for the object to undergo simple harmonic motion?
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Find the change in kinetic energy of a 1.0 kg fish leaping to the right at 12.0 m/s.
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Answer:

6J

Explanation:

Given parameters:

Mass of fish  = 1kg

Velocity  = 12m/s

Unknown:

Change in kinetic energy = ?

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       K.E  = \frac{1}{2}  m v²  

Now, insert the parameters and solve;

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A Bullet Off mass 100 gm is fired From A Gun Off mass 5 Kg. If the backward velocity of the gun's 5 m / s, what is forward veloc
Elena L [17]

Answer:

250 m/s

Explanation:

The mass of the bullet, m₁ = 100 g = 0.1 kg

The mass of the gun, m₂ = 5 kg

The backward velocity of the gun, v₂ = -5 m/s

Given that the momentum is conserved, we have;

The total initial momentum = The total final momentum

The gun and the bullet are at rest, therefore, we have;

The initial momentum = 0

The total final momentum = m₁·v₁ + m₂·v₂

Where;

v₁ = The forward velocity of the bullet

Therefore, we get;

m₁·v₁ + m₂·v₂ = 0

0.1 kg × v₁ + 5 kg × (-5 m/s) = 0

0.1 kg × v₁ = 5 kg × 5 m/s

v₁ = (5 kg × 5 m/s)/(0.1 kg) = 250 m/s

The forward velocity of the bullet, v₁ = 250 m/s

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Why is the weight of an object more on Earth than on the Moon?
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