Explanation:
Energy pyramid: is a model that shows the flow of energy from one feeding level to the next in an ecosystem. It compares the energy used by organisms at each trophic level.
Unit: kilocalories (kcal).
While Biomass pyramid is a statistical graph that shows the biomass present in a unit area of various trophic levels. It shows the relationship between biomass and trophic level. It quantifies the amount of biomass available in each trophic level of an energy community at a given time.
Unit: grams per square meter (g/m^2), or calories per square meter (K/m^2).
Answer:
0.75m/s^2
Explanation:
3.6-1.2=2.4 m/s (Change in velocity)
2.4/3.2=0.75 m/s/s or m/s^2
Answer:
electric field E = (1 /3 e₀) ρ r
Explanation:
For the application of the law of Gauss we must build a surface with a simple symmetry, in this case we build a spherical surface within the charged sphere and analyze the amount of charge by this surface.
The charge within our surface is
ρ = Q / V
Q ’= ρ V
'
The volume of the sphere is V = 4/3 π r³
Q ’= ρ 4/3 π r³
The symmetry of the sphere gives us which field is perpendicular to the surface, so the integral is reduced to the value of the electric field by the area
I E da = Q ’/ ε₀
E A = E 4 πi r² = Q ’/ ε₀
E = (1/4 π ε₀) Q ’/ r²
Now you relate the fraction of load Q ’with the total load, for this we use that the density is constant
R = Q ’/ V’ = Q / V
How you want the solution depending on the density (ρ) and the inner radius (r)
Q ’= R V’
Q ’= ρ 4/3 π r³
E = (1 /4π ε₀) (1 /r²) ρ 4/3 π r³
E = (1 /3 e₀) ρ r
Momentum = (mass) x (velocity)
Original momentum before the hit =
(0.16 kg) x (38 m/s) this way <==
= 6.08 kg-m/s this way <==
Momentum after the hit =
(0.16) x (44 m/s) that way ==>
= 7.04 kg-m/s that way ==>
Change in momentum = (6.08 + 7.04) = 13.12 kg-m/s that way ==> .
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Change in momentum = impulse.
Impulse = (force) x (time the force lasted)
13.12 kg-m/s = (force) x (0.002 sec)
(13.12 kg-m/s) / (0.002 sec) = Force
6,560 kg-m/s² = 6,560 Newtons = Force
( about 1,475 pounds ! ! ! )
Answer:
The normal strain along an axis oriented 45° from the positive x axis in the clockwise direction is -ε₀/2
Explanation:
Given that
From equation of normal strain in x direction:
Substituting the values:
