1) In the reference frame of one electron: 0.38c
To find the relative velocity of one electron with respect to the other, we must use the following formula:
where
u is the velocity of one electron
v is the velocity of the second electron
c is the speed of light
In this problem:
u = 0.2c
v = -0.2c (since the second electron is moving towards the first one, so in the opposite direction)
Substituting, we find:
2) In the reference frame of the laboratory: -0.2c and +0.2c
In this case, there is no calculation to be done. In fact, we are already given the speed of the two electrons; we are also told that they travel in opposite direction, so their velocities are
+0.2c
-0.2c
Distance = (1/2) (acceleration) (time)²
1.4m = (0.835 m/s²) (time)²
(time)² = (1.4/0.835) s²
<em>time = 1.295 s</em>
<span>Star a is more distant and is approximately 5 times as far away as star b
Parallax is the change in angle that one must do in order to observe the same object from different locations. The further away an object is, the smaller the parallax is. As the angles approach zero, the trig functions tend to be fairly linear. And 0.1 arc seconds and 0.02 arc seconds are close enough to zero for this to hold true.
Since the parallax for star a is smaller than the parallax for star b, it is the more distant star. And since 0.1 divided by 0.02 = 5, it is approximately 5 times further away than star b.</span>
Drinking Water - Direct
Our Eating Habits - Direct
Washing Clothes - Indirect
Answer:
Wavelength = 9.68 meters
Explanation:
Given the following data;
Speed = 300,000,000m/s
Frequency = 31 Megahertz to Hertz = 31 * 10⁶ Hz
To find the wavelength;
Wavelength = speed/frequency
Wavelength = 300,000,000/31,000,000
Wavelength = 9.68 meters
