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3 years ago

If the beam carries 1015 electrons per second and is accelerated by a 350 kV source, find the current and power in the beam.

1 answer:

3 0

To solve this problem we will apply the concept of current defined as the electron charge flow by the number of electrons per second. That is,

I = q*N

Here q is Flow of electric charge in one second and N the number of electron flow per second.

A the same time the power is described as the applied voltage for the current.

P = VI

We know the charge of electron, $q = 1.602 * 10^{-19}$ Coulombs, then the current is

$I = (1.602*10^{-19})(10^{15})$

$I = 0.1602 mA$

And the power in the Beam is

$P = VI$

$P = (350*10^3)(0.1602)$

$P = 0.05607 Watts$

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Which is a better conductor, a flagpole or a flag? Why?

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Answer:

flagpole

Explanation:

if it is about electricity then its flagpole

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2 years ago

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A car is traveling around a horizontal circular track with radius r = 210 m at a constant speed v = 23 m/s as shown. The angle θ

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Centripetal acceleration of car is given by formula

$a_c = \frac{v^2}{R}$

now plug in the values in this

$a_c = \frac{23^2}{210}$

$a_c = 2.52 m/s^2$

Part b)

At position A we have

x component of acceleration is given as

$a_x = -a_c cos23$

$a_x = -2.32 m/s^2$

Part c)

At position A we have

y component of acceleration is given as

$a_y = -a_c sin23$

$a_y = -0.98 m/s^2$

Part d)

At position B we have

x component of acceleration is given as

$a_x = -a_c cos53$

$a_x = -1.52 m/s^2$

Part e)

At position B we have

Y component of acceleration is given as

$a_y = a_c sin53$

$a_y = 2.01 m/s^2$

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3 years ago

if a bird at a constant speed going north and then turns west keeping the same speed does the momentum change

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The momentum does not change because he is going the same speed just a different way.

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3 years ago

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A student uses the right-hand rule as shown. an illustration with a right hand with fingers curled and thumb pointed up. what is

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The direction of the magnetic field in front of the wire closest to the student is on the left. The direction is found by the right-hand rule.

<h3>What is the right-hand rule?</h3>

The right-hand rule is a popular mnemonic for remembering how axes in three-dimensional space are oriented.

The fact that the three axes of three-dimensional space have two different orientations gives birth to the majority of the many left-hand and right-hand rules.

Using the right-hand rule, we can recall this diagram. Your thumb points in the direction of the magnetic force pushing on the moving charge

If you point your pointer finger in the direction of the positive charge and then your middle finger in the direction of the magnetic field.

To learn more about the right-hand rule refer to the link;

brainly.com/question/9750730

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2 years ago

An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the pos

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Answer:

The position is 8.18cm from the mirror.

Nature is b=virtual

Size is 1.82cm

Explanation:

Note that for a convex mirror, the image distance and the focal length are negative;

Given

Object height H0 = 4cm

object distance u = 18cm

Radius of curvature R = 30cm

Since f = R/2

f = 30/2

f = -15cm

Recall that:

$\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v} \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm$

Since the image distance is negative, this shows that the image is a virtual image.

To get the size:

$\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm$

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3 years ago