Answer:
it would take 3.26 seg for the stone to fall to the water
Explanation:
If we ignore air friction then:
h=h₀ + v₀*t -1/2*g*t²
where
h= coordinates of the stone in the y axis ( height of the stone relative to the surface of the water )
h₀ = initial coordinates of the stone ( height of the cliff relative to the surface of the water = 52 m )
v₀ = initial <u>vertical </u>velocity = 0 ( since the ball is kicked horizontally , has only initial horizontal velocity , and has 0 vertical velocity )
t = time to reach a height h
g = gravity = 9.8 m/s²
since v₀ =0
h= h₀ - 1/2*g*t²
h₀ - h = 1/2*g*t²
t= √[2(h₀ - h)/g]
when the stone hits the ground h=0 ( height=0) , then replacing values
t=√[2(h₀ - h)/g]=√[2(52 m- 0 m )/(9.8m/s²)] = 3.26 seg
t= 3.26 seg
it would take 3.26 seg for the stone to fall to the water
Um eclipse solar ocorre quando a lua fica entre a Terra e o sol, e a lua projeta uma sombra sobre a Terra. Um eclipse solar só pode ocorrer na fase da lua nova, quando a lua passa diretamente entre o sol e a Terra e suas sombras caem sobre a superfície da Terra.
Answer:
Option A. 39.2 m/s
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 4 s
Final velocity (v) =?
v = u + gt
Since the initial velocity (u) is 0, the above equation becomes:
v = gt
Thus, inputting the value of g and t, we can obtain the value of v as shown below:
v = 9.8 × 4
v = 39.2 m/s
Therefore, the velocity of the ball at 4 s is 39.2 m/s.
Answer:
-2.83 m/s²
Explanation:
- Initial velocity (u) = 34 m/s
- Final velocity (v) = 17 m/s
- Time taken (t) = 6 seconds
❖ Acceleration is defined as the rate of change in velocity with time.
→ a = (v - u)/t
- v denotes final velocity
- a denotes acceleration
- u denotes initial velocity
- t denotes time
→ a = (17 - 34)/6 m/s²
→ a = -17/6 m/s²
<h3>→ Acceleration = -2.83 m/s²</h3>
(Minus sign implies that the velocity is decreasing.)
