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leva [86]
3 years ago
15

Compare and contrast area and volume

Physics
1 answer:
katovenus [111]3 years ago
6 0
Area is a region bounded by a CLOSED path, curved path or path with line segments.  Area is usually a two dimensional physical quantity, a designated part on a plane.  An example the surface of a table, face of a wall or a ceiling.  It can also be a surface in 3-dimensions.  Its units are meter² or centimeter² or feet²  etc. A large agricultural field is a good example of an area.  Normally and ideally no object can reside or exist with in an area. An object requires a volume.  It is a collection of all points enclosed or bounded by the boundary or closed path.  It does not have any thickness.

Volume is a 3-dimensional quantity. A physical body occupies space with its material components. It is the amount of space occupied, that is its volume. Any existing body occupying some space has a mass and volume.  A mass having a volume, has surface area and thickness, a height perpendicular to its surface at each point on the surface.
It is expressed as meter³, feet³ etc.
Volume is a product of surface area (cross-section) and length - for example for a wire or rod.

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Three balls are in water. Ball 1 floats, with half of it exposed above the water level. Ball 2, with a density less than the den
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The magnitude of buoyancy force is equal to that of ball's weight.

Explanation:

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According to Darwin's theory of evolution, how does natural selection cause species to evolve over time?
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4 0
3 years ago
A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with
e-lub [12.9K]

Answer:

The direction of the car’s change in linear momentum is 149.04° West of North

Explanation:

Momentum is defined as the product of mass of a body and its velocity

Momentum = mass × velocity

Change in Momentum = mass × change in velocity

∆P = m∆v

∆P = m(v-u)

Given m = 1500kg

v = 25m/s

u = 15m/s

∆P = 1500(25-15)

∆P = 1500×10

∆P = 15,000kgm/s

Since the car first travels due East i.e +x direction

x = 25m/s

Travelling due south is negative y direction

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θ = tan^-1(y/x)

θ = tan^-1(-15/25)

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Since tan is negative in the second quadrant

θ = 180-30.96

θ = 149.04°

The direction of the car’s change in linear momentum is 149.04° West of North

5 0
4 years ago
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