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kirill [66]
3 years ago
10

What power does a toaster with 15 A of current and 20 Ωof resistance consume?

Physics
1 answer:
VLD [36.1K]3 years ago
8 0
Voltage= 300V
power= 4500W

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Are eggs a element, a compound, or a mixture
enyata [817]

Answer:

I'm gonna go with compund

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Which compound has the highest boiling point? Explain your reasoning. CH4 or CH3CH3
kogti [31]

The bigger molecule has more interactions and hence the higher b.p. CH3CH2OCH2CH3 is a bigger molecule than CH4 and CH3CH3, so has more dispersion forces. It also has dipole-dipole forces due to the polarised C-O bonds. CH3OH and CH3CH2OH have hydrogen bonds due to the very electronegative O atom bonded to the H atom

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In the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaning
olga2289 [7]

In the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.

<h3>What is an interval scale?</h3>

It should be noted that an interval scale means a measurement where the difference between the variables is meaningful and equal.

In this case, in the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.

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5 0
2 years ago
An electric motor can drive grinding wheel at two different speeds. When set to high the angular speed is 2000 rpm. The wheel tu
shutvik [7]

a) The initial angular speed is 209.3 m/s

b) The angular acceleration is -1.74 rad/s^2

c) The angular speed after 40 s is 139.7 rad/s

d) The wheel makes 1501 revolutions

Explanation:

a)

The initial angular speed of the wheel is

\omega_i = 2000 rpm

which means 2000 revolutions per minute.

We have to convert it into rad/s. Keeping in mind that:

1 rev = 2\pi rad

1 min = 60 s

We find:

\omega_i = 2000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=209.3 rad/s

b)

To find the angular acceleration, we have to convert the final angular speed also from rev/min to rad/s.

Using the same procedure used in part a),

\omega_f = 1000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=104.7 rad/s

Now we can find the angular acceleration, given by

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_i = 209.3 rad/s is the initial angular speed

\omega_f = 104.7 rad/s is the final angular speed

t = 60 s is the time interval

Substituting,

\alpha = \frac{104.7-209.3}{60}=-1.74  rad/s^2

c)

To find the angular speed 40 seconds after the initial moment, we use the equivalent of the suvat equations for circular motion:

\omega' = \omega_i + \alpha t

where we have

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 40 s, we find

\omega' = 209.3 + (-1.74)(40)=139.7 rad/s

d)

The angular displacement of the wheel in a certain time interval t is given by

\theta=\omega_i t + \frac{1}{2}\alpha t^2

where

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 60 s, we find:

\theta=(209.3)(60) + \frac{1}{2}(-1.74)(60)^2=9426 rad

So, the wheel turns 9426 radians in the 60 seconds of slowing down. Converting this value into revolutions,

\theta = \frac{9426 rad}{2\pi rad/rev}=1501 rev

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3 years ago
The common uses of radioactive elements in health care.
viva [34]

Answer: I-131, P-32, Sr-90, Co-60 & Technetium.

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