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3 years ago

Which statement best describes the relationship between temperature and thermal energy?

2 answers:

7 0

When temperature increases, particles in an object speed up, which means an increase in thermal energy. Since the particles are moving more now, the potential energy decreases, therefore kinetic energy increases.

Overall, when temp goes up, thermal energy goes up, which leads to an increase in kinetic energy.

Aleks [24]3 years ago

7 0

When temperature will increase, particles in an object speed up, which implies a rise in thermal energy. Since the particles armoving additional now, the potential energy decreases, so kinetic energy will increase.

Overall, once worker goes up, thermal energy goes up, that ends up in a rise in kinetic energy

Explanation:

Often we expect that heat and temperature are a constant issue. However, this can be not the case. Heat and temperature are associated with one another, however, are totally different ideas.

Heat is that the total energy of molecular motion during a substance whereas temperature may be a live of the common energy of molecular motion during a substance

When heat is transferred from one substance to a different, the warmth energy moves from the warmer substance to the colder substance.

The temperature may be a measure of however hot or cold a substance is. the upper the temperature of an object, the warmer is that the object

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The concept of derivatives and integrals allows to find the results for the questions are the motion of a particle where the speed depends on time are:

a)the position is: r = 2 t³ i + t² j

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h) The power is: P = 2m (36 t³ + 2t)

Kinematics studies the movement of bodies, looking for relationships between position, speed and acceleration.

a) They indicate the function of speed.

v = 6 t² i + 2t j

Ask the function of the position. The velocity is defined by the variation of the position with respect to time

v = $\frac{dr}{dt}$

dr = v dt

we substitute and integrate.

∫ dr = ∫ (6 t² i + 2t j) dt

r - 0 = $6 \frac{t^3 }{3} \ \hat i + 2 \frac{t^2}{2 \ \hat j }$

r = 2 t³ i + t² j

b) The position of the body on the y axis is a parabola and on the x axis it is a cubic function.

c) Acceleration is defined as the change in velocity with time.

$a = \frac{dv}{dt}$

a = $\frac{d}{dt} \ (6t^2 i + 2t j)$

a = 12 t i + 2 j

d) Newton's second law states that force is proportional to mass times the body's acceleration.

F = ma

F = m (12 t i + 2 j)

F = 5 12 t i + 2 j

F = 60 t i + 10 j

e) Torque is the vector product of the force and the distance to the origin.

τ = F x r

The easiest way to write these expressions is to solve for the determinant.

$\tau = \left[\begin{array}{ccc}i&j&k\\F_x&F_y&F_z\\x&y&z\end{array}\right]$

$\tau = \left[\begin{array}{ccc}i&j&k\\60t &10&0\\2t^3 &t^2&0\end{array}\right]$

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τ = 40 t³ k ^

f) Angular momentum

L = r x p

L =rx (mv)

L = m (rxv)

The easiest way to write these expressions is to solve for the determinant.

$\left[\begin{array}{ccc}i&j&k\\2t^3 &t^2&0\\6t^2&2t&0\end{array}\right]$

L = (4t³ - 6 t²) k

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K = ½ m v²

K = ½ m (6 t² i + 2t j) ²

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P = $\frac{dW}{dt}$ dW / dt

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W = ΔK

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a) The position is: r = 2 t³ i + t² j

b) The position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

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d) The force is: F = 60 t i + 10 j

e) The torque is: τ = 40 t³ k^

f) The angular momentum is: L = 4t³ - 6 t² k^

g) The kinetic energy is: K = 2 m t² (9t² +1)

h) The power is: P = 2m (36 t³ + 2t)

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