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patriot [66]
3 years ago
9

Which statement best describes the relationship between temperature and thermal energy?

Physics
2 answers:
choli [55]3 years ago
7 0
 <span>When temperature increases, particles in an object speed up, which means an increase in thermal energy. Since the particles are moving more now, the potential energy decreases, therefore kinetic energy increases. 

Overall, when temp goes up, thermal energy goes up, which leads to an increase in kinetic energy.</span>
Aleks [24]3 years ago
7 0
When temperature will increase, particles in an object speed up, which implies a rise in thermal energy. Since the particles ar<span>moving </span>additional now, the potential energy decreases, so kinetic energy will increase. 

Overall, once worker goes up, thermal energy goes up, that ends up in a rise in <span>kinetic energy

Explanation:

</span>
Often we expect<span> that heat and temperature </span>are a constant issue<span>. However, </span>this can be<span> not the case. Heat and temperature </span>are associated with one another<span>, </span>however, are totally different ideas<span>.

Heat </span>is that the<span> total energy of molecular motion </span>during a substance<span> </span>whereas<span> temperature </span>may be a live<span> of </span>the common<span> energy of molecular motion </span>during a<span> substance</span>

<span>When </span>heat<span> is transferred from one substance </span>to a different<span>, </span>the warmth<span> energy moves from </span>the warmer<span> substance to the colder substance.

The temperature </span>may be a measure<span> of </span>however<span> hot or cold a substance is. </span>the upper<span> the temperature of </span>an<span> object, </span>the warmer is that the<span> object</span>
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3 years ago
A 70mm long blockhas cross-section of 50mm by 10mm the block is subjected to forces 60KN (tension) on the 50mm by 10mm face and
sammy [17]

Answer:

970 kN

Explanation:

The length of the block = 70 mm

The cross section of the block = 50 mm by 10 mm

The tension force applies to the 50 mm by 10 mm face, F₁ = 60 kN

The compression force applied to the 70 mm by 10 mm face, F₂ = 110 kN

By volumetric stress, we have that for there to be no change in volume, the total pressure applied by the given applied forces should be equal to the pressure removed by the added applied force

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The pressure due to the force F₂ = 110 kN/(70 mm × 10 mm) = 157.142857 MPa

The total pressure applied to the block, P = 120 MPa + 157.142857 MPa = 277.142857 MPa

The required force, F₃ = 277.142857 MPa × (70 mm × 50 mm) = 970 kN

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3 years ago
A vector points -43.0 units
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Answer:

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To find the direction of this vector we need o find the angle that has a tangent of the y-component over the x-component:

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