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aniked [119]
3 years ago
5

What is the temperature of 0.645 mole of neon in a 2.00 L vessel at 4.68 atm?

Chemistry
1 answer:
storchak [24]3 years ago
7 0

Answer:

—96.03°C

Explanation:

We'll begin by writing out the information provided by the question. This includes:

Number of mole (n) = 0.645 mole

Volume (V) = 2.00 L

Pressure (P) = 4.68 atm

Temperature (T) =?

Recall: that the gas constant = 0.082atm.L/Kmol

With the ideal gas equation PV = nRT, the temperature of the gas can be obtained as follow:

PV = nRT

4.68 x 2 = 0.645 x 0.082 x T

Divide both side 0.645 x 0.082

T = (4.68 x 2) /(0.645 x 0.082)

T = 176.97 K

Now, We can also express the temperature obtained in celsius as shown below:

Temperature (celsius) = temperature (Kelvin) - 273

Temperature (celsius) = 176.97 - 273

Temperature (celsius) = —96.03°C

The temperature of the Neon gas is

—96.03°C

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Answer:

<span>Formula      New Combination                     Predicted Formula
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3) This is how you find the new formula to complete the chart.

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ii) AlCl₃             aluminum + fluorine 

Since fluorine is in the same group that Al, then you predict that in the new formula Cl is replaced by F leading to AlF₃

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Since tin is in the same group that C, you predict that in the new formula C is replaced by Sn leading to SnO₂

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