Question

Sydney Runs at 5m/s grabs a rope at the ground, how high does he swing?

Answer 1

Given:

The speed of Sydney is,

$v=5\text{ m/s}$

let the maximum height she reaches is h.

From the conservation of energy, we can write,

$\begin{gathered} \frac{1}{2}mv^2=mgh \\ h=\frac{v^2}{2g} \end{gathered}$

Substituting the values we get,

$\begin{gathered} h=\frac{5\times5}{9.8} \\ =2.55\text{ m} \end{gathered}$

Hence, the maximum height is 2.55 m.