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wel
3 years ago
10

The following data were obtained for a complex of nickel at 575 nm in a 1.00 cm cell. Using Microsoft Excel or some other graphi

ng program, construct a calibration plot and accurately calculate the molar absorptivity (ε) for the nickel-complex at 575 nm.
Standard # Nickel Complex Concentration (M) Absorbance
1 0.01 0.058
2 0.02 0.109
3 0.04 0.220
4 0.06 0.328

A. 0.184 M-1cm-1

B. 0.002 M-1cm-1

C. 5.425 M-1cm-1

D. Not Enough Information to Determine

Chemistry
1 answer:
kipiarov [429]3 years ago
7 0

Answer:

Check the explanation

Explanation:

It is basically known that the change in complex compositions of metal play a vital role in the conduction of molecular materials, which display atypical magnetic properties and conducting which also finds applicability in material chemistry, supramolecular and biochemistry, The electrochemical conduct of the nickel Ni(II) complexes was investigated in DMSO by cyclic voltammetry (CV), rotating coulometry and disc electrode (RDE).

The solution to the question above can be seen in the attached image below

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Convert 67 inches into a feet
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3 years ago
Which of the following actions would cause the volume of the chamber below to increase to 36.0 L?
Orlov [11]

Answer:

Option C. Triple the number of moles

Explanation:

From the ideal gas equation:

PV = nRT

Where:

P is the pressure

V is the volume

n is the number of mole

R is the gas constant

T is the absolute temperature.

Making V the subject of the above equation, we have:

PV = nRT

Divide both side by P

V = nRT / P

Thus, we can say that the volume (V) is directly proportional to both the number of mole (n) and absolute temperature (T) and inversely proportional to the pressure (P). This implies that and increase in either the number of mole, the absolute temperature and a decrease in the presence will cause the volume to increase.

Thus, the correct option is option C triple the number of moles. This can further be seen as illustrated below:

Initial volume (V1) = 12 L

Initial mole (n1) = 0.5 mole

Final mole (n2) = triple the initial mole = 3 × 0.5 = 1.5 mole

Final volume (V2) =?

From:

V = nRT / P, keeping T and P constant, we have:

V1/n1 = V2/n2

12/0.5 = V2/1.5

24 = V2/1.5

Cross multiply

V2 = 24 × 1.5

V2 = 36 L.

Thus Option C gives the correct answer to the question.

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