Answer:
Phenomenon
Explanation:
phe·nom·e·non
/fəˈnäməˌnän/
noun
1.
a fact or situation that is observed to exist or happen, especially one whose cause or explanation is in question:
"glaciers are unique and interesting natural phenomena"
synonyms
occurrence, event, happening, fact, situation, etc.
2.
a remarkable person, thing, or event:
"the band was a pop phenomenon just for their sales figures alone"
synonyms
marvel, sensation, wonder, prodigy, miracle, etc.
The canoe is moving at 14.1 m/s to the right after the collision.
Explanation:
According to the law of conservation of momentum, in absence of external forces the total momentum of the system must be conserved before and after the collision. So we can write:
where:
is the mass of the canoe
is the initial velocity of canoe (we take right as positive direction, and since the canoe is moving to the left, its velocity is negative)
is the final velocity of the canoe
is the mass of the raft
is the initial velocity of the raft
is the final velocity of the raft
Re-arranging the equation and substituting the values, we find: the final velocity of the canoe:

So, the canoe is moving at 14.1 m/s to the right after the collision.
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Answer:
Typically, atoms gain or lose electrons to achieve a stable electron configuration.
Explanation:
The natural light display called aurora borealis is located in the northern
hemisphere.
There are two types of aurora which are called aurora borealis and aurora
australis. The aurora borealis is located in the Northern hemisphere while
the aurora australis is located in the Southern hemisphere.
They receive their energy through the interaction of charged particles
on the Sun and Earth to produce the light display. An example
of the interaction involves solar wind with atoms of the upper atmosphere.
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Answer:
Explanation:
Answer:
Explanation:
Given that,
System of two particle
Ball A has mass
Ma = m
Ball A is moving to the right (positive x axis) with velocity of
Va = 2v •i
Ball B has a mass
Mb = 3m
Ball B is moving to left (negative x axis) with a velocity of
Vb = -v •i
Velocity of centre of mass Vcm?
Velocity of centre of mass can be calculated using
Vcm = 1/M ΣMi•Vi
Where M is sum of mass
M = M1 + M2 + M3 +...
Therefore,
Vcm=[1/(Ma + Mb)] × (Ma•Va +Mb•Vb
Rearranging for better understanding
Vcm = (Ma•Va + Mb•Vb) / ( Ma + Mb)
Vcm = (m•2v + 3m•-v) / (m + 3m)
Vcm = (2mv — 3mv) / 4m
Vcm = —mv / 4m
Vcm = —v / 4
Vcm = —¼V •i