Answer:
increase
Explanation:
According to Einstein's photoelectric equation; the energy of a photon striking a metal surface is related to the kinetic energy of the ejected photoelectron by the formula;
KE= hf - hfo
Where h is the planks constant, f and fo refer to the frequency of incident photon and the threshold frequency respectively.
Hence, we can clearly see from the foregoing that the kinetic energy of the ejected photoelectron is proportional to the frequency of the incident photon.
Hence, if the frequency of the incident photon is increased, the kinetic energy of the ejected photoelectron increases also.
Answer:
a)
Weight in Air = 0.3N
Weight in Water = 0.25N
Weight in Liquid = 0.24N.
Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)
= 0.3 – 0.25
= 0.5N.
b) R.D of Body = Density of Body/Density of Standard Fluid(Water).
There's a Derived Formula for RD.
I'm gonna Apply it here.
Ask me for the derivation in the Comment section if you need it.
RD = α/ρ = (Weight in Air) / (Upthrust Force)
Where
α = density of the Body(or reference substance)
ρ = density of standard fluid (water)
= 0.3/0.05 = 6.
c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)
Or we just go by that formula
RD of Liquid = Weight in Air/Upthrust(In Liquid)
We'll be using the Upthrust in that Liquid now.
= 0.3 – 0.24 = 0.06
RD = 0.3/0.06 = 5.
solution:
the kinetic energy acquired by the electron when it is accelerated y an electric field is
k=5.25\times10^-16j
the kinetic energy acquired by the electron will ne proportional to the potential difference between the plates across which the electric field is applied.it is given by,
e\Delta v = k
here,\delta v is the potential difference between the plates, e is the charge on an electron and k is the kinetic energy.
reassange the above expression
\delta v = \frac{k}{e}
the potential difference between the plates will be
\delta v = \frac{k}{e}
sunstitute 5.25 \times 10^-16j for k and 1.6 \times10^-19c for e is the above equation
\delta v =\frac{5.25\times10^-16j}{1.60\times10^-19c}
=3.28\times10^3v(\frac{1kv}{1000v})
=3.28kv
since the electrons will e accelerated towards the plate at higher potential.
hance p;ate b will be at higher potential
i don't know sorry
free to comment if you know the answer
