All categories

3 years ago

How will unbalanced forces affect the speed and direction of an object

Physics

1 answer:

azamat3 years ago

3 0

Answer:

Explanation:

Unbalanced forces will result in the presence of acceleration. The formula

F net = ma

says that if there is a net force present and the object in question has a mass, then an acceleration is present. Now acceleration is constant in this situation because nowhere does it say the acceleration is changing. If acceleration is constant then the velocity is increasing at a steady pace (think linear function!).

The direction of the object depends on the direction that the net force is in. If the net force is to the left, then that object will accelerate to the left.

Hope this helps :)

You might be interested in

A horizontal circular curve on a highway is designed for traffic moving at 60 km/h. If the radius of the curve is 150 m, and if

KengaRu [80]

Answer:

The value of the correct angle of banking for the road is $\theta = 67.76$ °

Explanation:

Given data

Velocity (v) = 60 $\frac{m}{s}$

Radius = 150 m

The velocity of the car in this case is given by

$v = \sqrt{r g \tan \theta}$

$v^{2} = r g \tan \theta$

$\tan \theta = \frac{v^{2} }{rg}$

Put all the values in above formula we get

$\tan \theta = \frac{60^{2} }{(150)(9.81)}$

$\tan \theta =$ 2.446

$\theta = 67.76$ °

Therefore the value of the correct angle of banking for the road is $\theta = 67.76$ °

4 0

2 years ago

The electric current running through the wire coil in an electric motor exerts force directly onto

Sveta_85 [38]

C) A powerful magnet

7 0

3 years ago

Read 2 more answers

A person uses 750 kcal on a long walk calculate the energy used for the walk in kilojoules

guapka [62]

Basically, this problem asks you to convert kilocalories (kcal) to kilojoules (kJ). Both are units of energy. To convert kcal to kJ, the equivalence is: 1 kcal = 4.184 kJ. Through dimensional analysis, the solution is as follows:

750 kcal * 4.184 kJ/1 kcal = 3,138 kJ

6 0

3 years ago

A proton, traveling with a velocity of 3.7 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 5.4

Vikki [24]

The magnetic force (Lorentz force) experienced by the proton in the magnetic field is given by
$F=qvBsin\theta=qvB$
since $\theta = 90^{\circ}$ , because the velocity v and the force F in this problem are perpendicular, and so also the angle $\theta$ between the velocity and the magnetic field B should be $90^{\circ}$ .

Let's find the magnitude of the magnetic field; this is given by
$B= \frac{F}{qv}= \frac{5.4\cdot 10^{-14}N}{1.6\cdot 10^{-19}C \cdot 3.7\cdot 10^6 m/s}=0.091 T$

To understand the direction, let's use the right-hand rule:
-index finger: velocity
- middle finger: magnetic field
- thumb: force

Since the velocity (index) points east and the force (thumb) points south, then the magnetic field (middle finger) points downwards. So we write:
B = -0.091 T

8 0

3 years ago

I'll give brainliest can someone help me with 2.4.1-2.4.3?with explanation.

KIM [24]

Answer:

220÷4=550 per hour

2.4.3 550×4=2200

hope it's right

8 0

2 years ago