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4 years ago

How will unbalanced forces affect the speed and direction of an object

Physics

1 answer:

azamat4 years ago

3 0

Answer:

Explanation:

Unbalanced forces will result in the presence of acceleration. The formula

F net = ma

says that if there is a net force present and the object in question has a mass, then an acceleration is present. Now acceleration is constant in this situation because nowhere does it say the acceleration is changing. If acceleration is constant then the velocity is increasing at a steady pace (think linear function!).

The direction of the object depends on the direction that the net force is in. If the net force is to the left, then that object will accelerate to the left.

Hope this helps :)

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Could a mixture be made only element and no compounds

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and the rest of what you're breathing right now is a mixture of elements.

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3 years ago

Which was not a part of faradays law regarding the induced voltage in a coil?

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3 years ago

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A solution is a homogeneous mixture of one or more solutes dissolved in a solvent. A specific volume of solvent is only able to

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C. Supersaturated

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3 years ago

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A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that a

scoundrel [369]

To solve this problem we will apply the concepts related to magnetic flux and induced voltage. This last expression understood as the variation of the magnetic flux over time and, in turn, the magnetic flux expressed as the variation of the magnetic field in a certain area.

Magnetic flux through the circular coil is given as

$\Phi_C = B(\pi r^2)$

The induced voltage is the change of the magnetic flux across the time, then

$\epsilon_{emf,C} = \frac{B(\pi r^2)}{t}$

At the same time the magnetic flux through the square coil would be given as,

$\Phi_S = B(r^2)$

And the induced voltage EMF will be

$\epsilon_{emf,s} = \frac{B(r^2)}{t}$

Equating both expression we have

$\epsilon_{emf,s} = \frac{\epsilon_{emf,C}tr^2}{\pi r^2t}$

$\epsilon_{emf,s} = \frac{0.74V}{\pi}$

$\epsilon_{emf,s} = 0.23355V$

Therefore the emf induced in the square coil is 0.23355V

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3 years ago

Sam, whose mass is 75 kg, straps on his skis and starts down a 50-m-high, 20 frictionless slope. A strong headwind exerts a hori

LenaWriter [7]

Answer:

Explanation:

Sam mass=75kg

Height is 50m

20° frictionless slope

Horizontal force on Sam is 200N

According to the work energy theorem, the net work done on Sam will be equal to his change in kinetic energy.

Therefore

Wg - Ww =∆K.E

Note initial the body was at rest at top of the slope.

Then, ∆K.E is K.E(final) - K.E(initial)

K.E Is given as ½mv²

Since initial velocity is zero then, K.E(initial ) is zero

Therefore, ∆K.E=½mVf²

Wg is work done by gravity and it is given by using P.E formulas

Wg=mgh

Wg=75×9.8×50

Wg=36750J

Ww is work done by wind and it's is given by using formulae for work

Work=force × distance

Ww=horizontal force × horizontal distance

Using Trig.

TanX=opposite/adjacent

Tan20=h/x

x=h/tan20

x=50/tan20

x=137.37m

Then,

Ww=F×x

Ww=200×137.37

We=27474J

Now applying the formula

Wg - Ww =∆K.E

36750 - 27474 =½×75×Vf²

9276=37.5Vf²

Vf²=9275/37.5

Vf²= 247.36

Vf=√247.36

Vf=15.73m/s

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4 years ago