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diamong [38]
2 years ago
13

The mass of the uniform cantilever is 1100 kg. Determine the force on the beam at A. Determine the force on the beam at B. Use C

lockwise as the negative direction.

Physics
1 answer:
Mashcka [7]2 years ago
8 0

Answer:

Force A=-−2,697.75 N

Force B=13, 488.75 N

Explanation:

Taking moments at point A, the sum of clockwise and anticlockwise moments equal to zero.

25 mg-20Fb=0

25*1100g=20Fb

Fb=25*1100g/20=1375g

Taking g as 9.81 then Fb=1375*9.81=13,488.75 N

The sum of upward and downward forces are same hence Fa=1100g-1375g=-275g

-275*9.81=−2,697.75. Therefore, force A pulls downwards

Note that the centre of gravity is taken to be half the whole length hence half of 50 is 25 m because center of gravity is always at the middle

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7nadin3 [17]
Using the precise speed of light in a vacuum (299,792,458 \ \frac{m}{s}), and your given distance of 1.152 * 10^{8} km, we can convert and cancel units to find the answer. The distance in m, using \frac{1000 \ m}{1 \ km}, is 1.152 * 10^{11} m. Next, for the speed of light, we convert from s to min, using \frac{1 \ min}{60 \ s}, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

7 0
3 years ago
A uniformly charged thin ring has radius 15.0 cm and total charge 20.0 nC . An electron is placed on the ring's axis a distance
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Answer:

b) 1.67×10^7 m/s

Explanation:

The solution is attached in the attachment section

8 0
2 years ago
4. What is the acceleration of the car in each section?<br> b<br> с<br> d<br> a
makvit [3.9K]

Answer:

0-4 acceleration comes at 12 m/s where (B) stagnates at 12 m/s and remains for 4 seconds (C) is breaks being activated slowing the car to 6 m/s in 2 seconds and (D) over the course of 4 seconds brings the car to 10 m/s.

Explanation:

3 0
2 years ago
Read 2 more answers
Starting from rest, a person runs with a constant acceleration, traveling 40 meters in 10 seconds. What is their final velocity?
Assoli18 [71]

Answer:

Final velocity v = 8.944 m/sec

Explanation:

We have given distance S = 40 meters

Time t = 10 sec

As it starts from rest so initial velocity u = 0

From second equation of motion s=ut+\frac{1}{2}at^2

40=0\times 10+\frac{1}{2}a10^2

a=0.8944m/sec^2

Now from first equation of motion v=u+at, here v is final velocity, u is initial velocity, a is acceleration and t is time

So v=u+at=0+0.8944\times 10=8.944m/sec

6 0
3 years ago
A 17 kg box sitting on a shelf has a potential energy of 350 J. How high is the shelf? Round your answer to the nearest whole nu
Free_Kalibri [48]
Potential energy is mass * gravity * height. (m*g*h).

350 = 17*9.8*h   <--350 is its energy, 17kg is its mass, and 9.8 is gravity's acceleration on the object. We now just need to solve for h.

h = 350/(17 * 9.8) =  2.1 meters, which, when rounded to the nearest whole meter, is 2 meters.

The shelf is 2 meters high.

3 0
2 years ago
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