Answer:a) The linear speed of the rotating merry-go-round is 1.884 m/s.
b) The acceleration of the rotating merry-go-round device is
.
Explanation:
a) linear speed of the device:
Distance =
Child seated 1.2 meters from the center, which means that radius ,r = 1.2 meters
Time taken to complete one revolution = 4.0 seconds

The linear speed of the rotating merry-go-round is 1.884 m/s.
b) Acceleration
Linear velocity ,v = 1.884 m/s


The acceleration of the rotating merry-go-round device is
.
Hello!
what is the net force of this object if it is 400 N up and 600 N down?
In this case, as the meanings of the vectors are opposite, one of the forces receives the negative signal and thus a piece of the other vector is drawn, as shown in the figure. And to know the module of the resultant force, if it subtracts the modules of the forces.



Answer:
200N
______________________________
I Hope this helps, greetings ... Dexteright02! =)
Answer:200 Mpa
Explanation:
Given that diameter of cylinder = d = 1-25cm = 1.25 100 =0.0125m
Load or mass = m = Stress 0 = ? 2500kg
Solution: Formula N = F A
Area of Cross-section of cylinder = A=πr2 A = π(d/2) 2
= π(d2/4)
=(3.14)(0.0125)2/4
A = 1.226x10-4
F ・ mg = = F A 24500 2500 x 9.8 = 24500 N
1-226x10-4
1998 36 867.9
= 200 x 106 Pa
= 200 MPa
*Hope it helps you*
Good luck
Answer:
The displacement of particles is perpendicular to the direction of wave motion.