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2 years ago

SINGLE CORRECT OBJECTIVE

Physics

1 answer:

natali 33 [55]2 years ago

8 0

Answer:

True

Explanation:

Formula for speed is;

Speed = distance/time

Now, if an object covers an equal distance in equal time intervals, it means the speed will remain the same.

For example if an object covers 3 m every 1 second it means speed will always be; 3/1 = 3 m/s.

Thus the statement is correct.

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Suppose that a balloon is being filled with air at a rate of 10 cm3/s. (Assume that theballoon is a perfect sphere.) At what rat

Basile [38]

Answer:

Therefore the surface area of the balloon is increased at 4 cm³/s.

Explanation:

The balloon is being filled with air at a rate of 10 cm³/s

It means the volume of the balloon is increased at a rate 10 cm³/s.

i.e $\frac{dv}{dt} =10 cm^3/s$

Consider r be the radius of the balloon.

The volume of of a sphere is

$v=\frac{4}{3} \pi r^3$

Differentiate with respect to t

$\frac{dv}{dt} =\frac{4}{3} \pi \times 3r^2\frac{dr}{dt}$

$\Rightarrow 10 =4\pi r^2\frac{dr}{dt}$

$\Rightarrow \frac{dr}{dt}=\frac{10}{4\pi r^2}$

The surface of area of the balloon is(S) = $4\pi r^2$

$S=4\pi r^2$

Differentiate with respect to t

$\frac{dS}{dt} =4\pi\times2r\frac{dr}{dt}$

$\Rightarrow \frac{dS}{dt} =8\pi r\frac{dr}{dt}$

Putting the value of $\frac{dr}{dt}$

$\Rightarrow \frac{dS}{dt} =8\pi r\times\frac{10}{4\pi r^2}$

$\Rightarrow \frac{dS}{dt} =\frac{20}{ r}$

Given that r = 5 cm

$[\frac{dS}{dt}]_{r=5} =\frac{20}{ 5}$ =4 cm³/s

Therefore the surface area of the balloon is increased at 4 cm³/s.

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3 years ago

Electricity is the flow of electrons. The questions relate to how electricity is quantified. Electrons are charged particles. Th

xxTIMURxx [149]

The amount of charge that passes per unit time is called <em>electric current</em> .

Current has dimensions of [Charge] / [Time] .

It's measured and described in units of ' Ampere ' .

1 Ampere means 1 Coulomb of charge passing a point every second.

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2 years ago

What are the two factors that determine a material's density?

Juliette [100K]

Mass and volume are the 2 factors to determine density

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3 years ago

A man does 500 J of work pushing a car a distance of 2 m. How much force does he apply? Assume there is no friction.

Dmitry [639]

The correct answer is A. 250N

Work is a product of force and distance.

That is, work done=force×distance

Therefore substituting for the values in the question:

500J=force×2m

force= 500Nm/2m=250N

another unit for work done is Nm as force as the SI unit of force is newtons and distance in meters

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2 years ago

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Why did the “yielders” conform in Asch’s experiment?

svet-max [94.6K]

Answer:

Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.

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2 years ago