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BaLLatris [955]
3 years ago
10

3 Drag each tile to the correct location. Classify the reactions as endothermic or exothermic. The reaction between ammonium nit

rate and water absorbs heat from the surrounding environment. Three drops of concentrated sulfuric acid added to 100 milliliters of water in a beaker makes the beaker hot. Ammonium chloride dissolved in a beaker of water makes the beaker cold. Uranium atoms are split to produce nuclear energy. Water separates into hydrogen and oxygen when an electric current is run through it. Methane and oxygen are combined to produce methanol and heat. Reset Next Previous 3 Next Post Test: Chemical Reactions Submit Test Reader Tools Info Save & Exit © 2018 Edmentum. All rights reserved.
Chemistry
1 answer:
Lorico [155]3 years ago
8 0

In an exothermic reaction heat is released by a chemical reaction. In an endothermic reaction heat is absorbed by a chemical reaction.  

The reaction between ammonium nitrate and water absorbs heat from the surrounding environment. Endothermic Reaction  

Three drops of concentrated sulfuric acid added to 100 milliliters of water in a beaker makes the beaker hot. Exothermic Reaction  

Ammonium chloride dissolved in a beaker of water makes the beaker cold. Endothermic Reaction  

Uranium atoms are split to produce nuclear energy. Exothermic Reaction  

Water separates into hydrogen and oxygen when an electric current is run through it. Endothermic Reaction  

Methane and oxygen are combined to produce methanol and heat. Exothermic Reaction  




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4 0
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PLEASE HELP ME I DONT WANT TO FAIL
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What is the name of Fe(OH)3
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3 years ago
How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)
11Alexandr11 [23.1K]

98.56 dm^3 of oxygen at STP would be required to react completely with 38.8g of propane.

<u>Given that :</u>

molar mass of propane = 44 g/mol

mass of propane = 38.8 g

∴ Moles present in 38.8 g of propane = \frac{38.8}{44} = 0.88 mole

<u>applying rule of balanced equations </u>

1 mole of propane = 5 moles of oxygen

0.88 mole of propane =  5 * 0.88 = 4.4 moles of oxygen

Note : volume of 1 mole of oxygen at STP = 22.4 dm^3

∴Total volume of oxygen required at STP = 22.4 * 4.4 = 98.56 dm^3

Hence we can conclude that the volume of oxygen at STP required to react completely 98.56 dm^3

Learn more : brainly.com/question/16998374

5 0
2 years ago
How much heat energy is required to raise the temperature of 0.360 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of co
AVprozaik [17]
MThe  heat  energy  required  to  raise  the  temperature   of  0.36Kg   of  copper   from   22 c   to  60  c  is  calculate  using  the  following  formula

MC delta T
m(mass)=  0.360kg  in  grams  =  0.360  x1000 = 360 g
  c(specific  heat  energy)  =  0.0920  cal/g.c
delta T =  60- 23  = 37  c

heat  energy is therefore=  360g   x0.0920 cal/g.c  x 37  c=  1225.44  cal

5 0
3 years ago
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