1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vlad1618 [11]
4 years ago
15

After passing through pyruvate dehydrogenase and the citric acid cycle, one mole of pyruvate will result in the formation of ___

_____ moles of carbon dioxide and ________ mole(s) of ATP (or GTP).
Chemistry
1 answer:
mamaluj [8]4 years ago
7 0

Answer:

The answer to be filled in the respective blanks in question is

3 and 1

Explanation:

So, we know that the formation of cabon-dioxide mole and that of Adenosin-Tri-Phosphate (ATP) moles will be in the ratio of 3:1 i.e., three carbon-di-oxide moles and 1 ATP mole.

Therefore, we can say that one pyruvate mole when passed through citric acid cycle and pyruvate dehydrogenase yields carbon-di-oxide and ATP moles in the ratio 3:1

 

You might be interested in
Which metal is heaviest ?
const2013 [10]
Titanium is the haviest metal .
8 0
3 years ago
Read 2 more answers
What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare
Schach [20]

<span> </span>

Answer is: volume is 20 mL.<span>
c</span>₁(CH₃COOH) = 2,5 M.<span>
c</span>₂(CH₃COOH) = 0,5 M.<span>
V</span>₂(CH₃COOH) = 100 mL.<span>
V</span>₁(CH₃COOH) = ?<span>
c</span>₁(CH₃COOH) · V₁(CH₃COOH) = c₂(CH₃COOH) · V₂(CH₃COOH).<span>
2,5 M · V</span>₁(CH₃COOH) = 0,5 M · 100 mL.<span>
V</span>₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.<span>
V</span>₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.

8 0
3 years ago
Calculate the ionic strength of a solution of iron (iii) carbonate, fe2(co3)3 of concentration 0.020 mol dm
Ede4ka [16]
E=b(x^3)×co3x{fe2}+13^3
6 0
3 years ago
The Difference Between an Alloy and an Amalgam
Delicious77 [7]

Mixtures or combinations of various different metals or metallic substances form things called alloys. An alloy composed of mercury and other metal (or metals) forms "amalgam". When a true alloy is created, the component metals are combined together at a temperature which is greater than the melting point of all of them.

Also, it helps to remember the word "amalgamate", which means "to alloy (a metal) with mercury" according to Dictionary.com.


Hope this helped :)


(btw I'm like 3 brainliest answers away from my next rank so could you...you know... :)

6 0
4 years ago
The movement of broken down pieces of rock from one place to another is called
Dvinal [7]

Answer:

The answer I believe is B. Erosion

Explanation:

Just sounds better than all the other choices.

7 0
3 years ago
Read 2 more answers
Other questions:
  • A sodium atom has 1 valence electron in its third shell. What will it do when forming an ion? A. gain 1 valence electron B. lose
    13·1 answer
  • Draw arrows for all of the attractive and repulsive forces between the negatively charged electrons and positively charged proto
    15·1 answer
  • Which of the following would result in butyl phenyl ether as the major product? a. Reaction of phenoxide with 1-bromobutane b. R
    10·1 answer
  • Write the molecular equation and net ionic equation for the reaction of hydroiodic acid and potassium hydroxide. Include phases
    8·1 answer
  • What mass (g) of ammonium acetate contains 8.334 x 1024 hydrogen atoms?
    11·1 answer
  • Explain why quilt is a better insulator than a woolen blanket of the same thickness ​
    15·1 answer
  • At 40km up in the atmosphere the pressure is 3.8 kPa. I release a balloon with a volume of 30.0
    15·1 answer
  • Compare the way that frogs breathe when they are tadpoles with the way frogs breathe when they are adults.
    7·2 answers
  • The balmer thermometer uses the atomic transitions of what element to measure the temperature of stars?
    13·1 answer
  • How many valence electrons are there in an argon atom?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!