Answer:
Where the greatest electron density is. And isn’t. Look at water. H-O-H.
The oxygen has more electrons, AND 2 lone pairs - the Hydrogens will be partially positive, and so such a way shows the polarity; am arrow with +-> on the Hydrogen area. The “point” will have a negative sign; usually these are drawn as “partially positive” & “partially negative”, but I can’t draw that. Sorry.
Explanation:
Kekulé/Vant Hoff and Le Bel?
Answer:
6 moles
Explanation:
Take a look at the balanced chemical equation for this synthesis reaction
N
2(g]
+
3
H
2(g]
→
2
NH
3(g]
Notice that you have a
1
:
3
mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.
So, if you have
2
moles of nitrogen taking part in the reaction, you will need
2
moles N
2
⋅
3
moles H
2
1
mole N
2
=
6 moles H
2
NH4Cl + heat forms NH4 + + Cl-
Answer:
The given reaction in your problem is the ionic equation for an acid (carbonic acid) reacting with a base (sodium hydroxide). All components of the reaction are then written in ionic form except for reactant weak electrolytes and the driving force product compound of the reaction (H2O). See following explanation.
Explanation:
Metathesis Rxn: molecular equation of rxn
H₂CO₃(aq) + 2NaOH(aq) => Na₂CO₃(aq) + 2H₂O(l)
Ionic Equation: shows all components of the reaction
H₂CO₃(aq) + 2Na⁺(aq) + 2OH⁻(aq) => 2Na⁺(aq) + CO₃²⁻(aq) + 2H₂O(l)
H₂CO₃(aq) wk. electrolyte and H₂O(l) driving force compound are not shown ionized in ionic equation. Only strong electrolytes that ionize 100%; i.e., salts and strong acids and bases.
Net Ionic Equation: shows only the reactive components without the spectator ions (nonreactive components), in this case, the Na⁺(aq) ions.
H₂CO₃(aq) + 2OH⁻(aq) => CO₃²⁻(aq) + 2H₂O(l)
