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vfiekz [6]
3 years ago
15

Under what condition is phase rule applied​

Chemistry
1 answer:
Pavel [41]3 years ago
4 0

Answer:

Under the equilibrium condition

Explanation:

according to the phase rule given by Willard Gibbs, under the condition where the equilibrium between the number of phases is not affected by the gravity, electricity magnetic force or by surface action and the system is under constant temperature, pressure and concentration then the degrees of freedom(F) is proportional to the concerntration (C) and the Phases(P) at equilibrium condition.  

the expression is given as : F= C-P+2

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What is the pressure in a 5.00 L tank with<br> 7.10 moles of oxygen at 39.3 °C?
Katena32 [7]

Answer:

36.4 atm

Explanation:

To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = ? atm                         R = 0.0821 L*atm/mol*K

V = 5.00 L                       T = 393 °C + 273.15 = 312.45 K

n = 7.10 moles

PV = nRT

P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)

P(5.00 L) = 182.130

P = 36.4 atm

8 0
2 years ago
The ideal gas law tends to become inaccurate when:
Maslowich

Answer:yes

Explanation:

4 0
3 years ago
Equilibrium is established in a reversible reaction when
avanturin [10]
The correct answer among the options given is B. . When the forward and reverse paths of a change occur at the same rate, <span>the system is in equilibrium specifically in dynamic equilibrium.<span> Dynamic equilibrium is the balance in a process that is continuing. </span></span>
6 0
4 years ago
Please answer ASAP!!
Alenkasestr [34]

Answer:

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

Cu²⁺ + 2e⁻ → Cu E° = 0.52V

Ag⁺ + 1e⁻ → Ag E° = 0.80V

As the Cu will be oxidized:

Cu → Cu²⁺ + 2e⁻

The cell potential is:

E°Cell = E°cathode(reduced) - E°cathode(oxidized)

E°cell = 0.80V - (0.52V)

E°cell = 1.32V

Right answer is:

<h3>C.0.28 V </h3>

<h3 />

4 0
3 years ago
When Al(NO3)3 is separated into its ions, how is it written?
nikklg [1K]
Al (+3)
NO3 (-1)
So basically you need 3 NO3 and one Al to produce Al (NO3)3
3 0
4 years ago
Read 2 more answers
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