Answer is: f<span>ormula for the hydrated compound is CuSO</span>₄·3H₂O.
ω(H₂O) = 25,3% = 0,253.
ω(CuSO₄) = 100% - 25,3%.
ω(CuSO₄) = 74,7% = 0,747.
ω(H₂O) : M(H₂O) = ω(CuSO₄) : M(CuSO₄).
0,253 : M(H₂O) = 0,747 : 159,6 g/mol.
M(H₂O) = (0,253 · 159,6 g/mol) ÷ 0,747.
M(H₂O) = 54 g/mol.
N(H₂O) = 54 g/mol ÷ 18 g/mol.
N(H₂O) = 3.
Answer:Increased the number of molecular collisions and increased the reaction rate
Explanation:
Control: skunk
Independent: poking (the skunk)
dependent: emission of toxic fumes
We are given with 500 mg of sucrose dissoved in a 200 ml of water. The concentration of the solid is amount of solute per volume of the solvent. The concnetration can be expressed as 2.5 grams sugar per liter water or 250 mg per 100 ml water.