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aleksley [76]
3 years ago
9

As the temperature of a liquid increases, the solubility of a solid in the liquid

Physics
1 answer:
nexus9112 [7]3 years ago
4 0
D, it depends. For water, the solubility increases as it get hotter, up to 100 degrees, but in some cases, liquids behave the opposite way.
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sesenic [268]

Answer:1. A chair leaning on a wall

Explanation:

5 0
3 years ago
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explain why astronauts around the earth either in spaceship, a space station, or on a spacewalk appear to be weightless but are
IrinaK [193]

Answer:

Zero gravity

Explanation:

Astronauts around the earth either in spaceship, a space station or on a space walk appear to be weightless because of the zero gravity in such environment.

Weight is a function of the mass and acceleration due to gravity a body has.

   Weight  = mass  x  acceleration due to gravity

In a place where acceleration due to gravity is 0, the weight would be zero and a person would appear to be weightless.

6 0
3 years ago
Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te
solong [7]

To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

The intrinsic carrier concentration is the number of electrons in the conduction band or the number of holes in the valence band in intrinsic material. This number of carriers depends on the band gap of the material and on the temperature of the material.

In general, this can be written mathematically as

\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}

Both are identical semiconductor but the difference is band gap which is:

E_{g1} = 1.1eV

n_{i1} = 1*10^{19}m^{-3}

E_{g2} = 1.2eV

T=300K

The ratio between the two phases are given as:

\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}

\frac{\eta_{i1}}{\eta_{i2}} = e^{\frac{E_{g2}-E_{g1}}{2KT}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{-1.932367}

\frac{\eta_{i1}}{\eta_{i2}} =0.145

Therefore the ratio of intrinsic carrier densities for the two materials at room temperature is 0.145

7 0
4 years ago
An object is dropped from a height of 75.0 m above ground level. (a) Determine the distance traveled during the first second. (b
lys-0071 [83]

Answer:

a)Distance traveled during the first second = 4.905 m.

b)Final velocity at which the object hits the ground = 38.36 m/s

c)Distance traveled during the last second of motion before hitting the ground = 33.45 m

Explanation:

a) We have equation of motion

             S = ut + 0.5at²

     Here u = 0, and a = g

              S = 0.5gt²

    Distance traveled during the first second ( t =1 )

              S = 0.5 x 9.81 x 1² = 4.905 m

   Distance traveled during the first second = 4.905 m.

b)  We have equation of motion

            v² = u² + 2as

      Here u = 0, s= 75 m and a = g

           v² = 0² + 2 x g x 75 = 150 x 9.81

           v = 38.36 m/s

      Final velocity at which the object hits the ground = 38.36 m/s

c) We have S = 0.5gt²

                   75 = 0.5 x 9.81 x t²

                    t = 3.91 s

   We need to find distance traveled last second

   That is

          S = 0.5 x 9.81 x 3.91² - 0.5 x 9.81 x 2.91² = 33.45 m

   Distance traveled during the last second of motion before hitting the ground = 33.45 m

       

3 0
4 years ago
Which units are used to express kinetic energy?
labwork [276]

Answer:

The SI units for energy is Joules.

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4 years ago
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