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3 years ago

How do gravitational and electic force compare

1 answer:

3 0

Electric Forces. ... Just like objects that have mass exert gravitational forces on each other, objects that are charged will also exert electric forces on each other. The electric force is directly proportional to the charge of the two objects and inversely proportional to the distance between them squared.

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You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f

Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

$u = 0m/s$

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

$s = ut+\frac{1}{2} at^2$

Replacing,

$1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2$

$u =6.4013m/s$

The height of the acorn above the meter stick can be calculated as,

$v^2 = u^2 +2gh$

$h = \frac{v^2-u^2}{2g}$

$h = \frac{6.4013^2-0^2}{2(9.8)}$

$h = 2.0906m$

Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is

$h = 2.0906+1.87$

$h = 3.9606m$

4 0

4 years ago

A person shouting at the top of his lungs emits aboue 1.0 w of energy as sound waves. What is the sound intensity 1.0 m from suc

umka21 [38]

Answer:

$I=0.0795\ W/m^2$

Explanation:

When a person shouts it emits 1 W of energy as sound waves, P = 1 W

Let I is the sound intensity 1 meters from such a person. We know that the power per unit area is called the sound intensity of the person. Its formula is given by :

$I=\dfrac{P}{A}$

$I=\dfrac{P}{4\pi r^2}$

$I=\dfrac{1\ W}{4\pi (1\ m)^2}$

$I=0.0795\ W/m^2$

So, the sound intensity of such a person is $0.0795\ W/m^2$ . Hence, this is the required solution.

3 0

4 years ago

When a light bulb is connected to a 4.5 V battery, a current of 0.16 A passes through the bulb filament. What is the resistance

larisa [96]

Answer:

R = 28.125 ohms

Explanation:

Given that,

The voltage of a bulb, V = 4.5 V

Current, I = 0.16 A

We need to find the resistance of the filament. Using Ohm's law,

V = IR

Where

R is the resistance of the filament

So,

$R=\dfrac{V}{I}\\\\R=\dfrac{4.5}{0.16}\\\\R=28.125\ \Omega$

So, the resistance of the filament is equal to 28.125 ohms.

5 0

3 years ago

A car manufacturer claims an enginerring breakthrough, since it successfully reduced its interior noise level from 65dB to 55 dB

Stells [14]

Yes, that is truly amazing.

They significantly reduced the noise's intensity by 90%, that might be proper reaction.

<h3>What is noise?</h3>

Unwanted sound that is regarded loud, unpleasant, or disruptive to hearing is called noise.
Physically speaking, there is no difference between unwanted sound and desired sound because both are vibrations traveling through a medium like air or water.
When the brain receives and interprets a sound, a difference occurs.
Decibels are used to measure sound (dB).
A motorcycle engine operating is roughly 95 dB louder than regular conversation, which is around 60 dB louder than a whisper.
Your hearing may begin to be harmed if exposed to noise over 70 dB for an extended period of time.
Your ears can suffer instant damage from loud noise above 120 dB.

<h3>What is sound intensity?</h3>

The power carried by sound waves per unit area in a direction perpendicular to that region is known as sound intensity or acoustic intensity.
The watt per square meter is the SI measure of intensity, which also covers sound intensity.

Learn more about sound here:

brainly.com/question/14595927

#SPJ4

5 0

2 years ago

a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the

erma4kov [3.2K]

The emerging velocity of the bullet is <u>71 m/s.</u>

The bullet of mass <em>m</em> moving with a velocity <em>u</em> has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed <em>v</em> when it emerges from the block.

If the block exerts a resistive force <em>F</em> on the bullet and the thickness of the block is <em>x</em> then, the work done by the resistive force is given by,

$W=Fx$